Question

我有下一个问题，我有这个多维数组：

另外，我有以下功能：

public function transformValue($array = [], $level = 1) {
    $return = [];
    foreach($array as $key => $value){
        if(is_array($value)){
            $this->transformValue($value, $level + 1);
        } else{
            $return[$key] = $value;
        }
    }
    return $return;

}

此函数接收此多数组作为参数，因为我需要按如下方式对其进行规范化：

Array
(
    [start_date] => 2016-07-14 07:00
    [end_date] => 2016-07-14 07:20
    [type] => 2
)
Array
(
    [start_date] => 2016-07-14 07:20
    [end_date] => 2016-07-14 07:40
    [type] => 2
)
Array
(
    [start_date] => 2016-07-14 07:40
    [end_date] => 2016-07-14 08:00
    [type] => 2
)
Array
(
    [start_date] => 2016-07-14 08:00
    [end_date] => 2016-07-14 08:15
    [type] => 3
)
Array
(
    [start_date] => 2016-07-14 08:15
    [end_date] => 2016-07-14 08:30
    [type] => 3
)
Array
(
    [start_date] => 2016-07-15 07:00
    [end_date] => 2016-07-15 07:20
    [type] => 2
)
Array
(
    [start_date] => 2016-07-15 07:20
    [end_date] => 2016-07-15 07:40
    [type] => 2
)
Array
(
    [start_date] => 2016-07-15 07:40
    [end_date] => 2016-07-15 08:00
    [type] => 2
)
Array
(
    [start_date] => 2016-07-15 08:00
    [end_date] => 2016-07-15 08:15
    [type] => 3
)
Array
(
    [start_date] => 2016-07-15 08:15
    [end_date] => 2016-07-15 08:30
    [type] => 3
)
Array
(
    [start_date] => 2016-07-18 07:00
    [end_date] => 2016-07-18 07:20
    [type] => 2
)
Array
(
    [start_date] => 2016-07-18 07:20
    [end_date] => 2016-07-18 07:40
    [type] => 2
)
Array
(
    [start_date] => 2016-07-18 07:40
    [end_date] => 2016-07-18 08:00
    [type] => 2
)
Array
(
    [start_date] => 2016-07-18 08:00
    [end_date] => 2016-07-18 08:15
    [type] => 3
)
Array
(
    [start_date] => 2016-07-18 08:15
    [end_date] => 2016-07-18 08:30
    [type] => 3
)
Array
(
    [start_date] => 2016-07-19 07:00
    [end_date] => 2016-07-19 07:20
    [type] => 2
)
Array
(
    [start_date] => 2016-07-19 07:20
    [end_date] => 2016-07-19 07:40
    [type] => 2
)
Array
(
    [start_date] => 2016-07-19 07:40
    [end_date] => 2016-07-19 08:00
    [type] => 2
)
Array
(
    [start_date] => 2016-07-19 08:00
    [end_date] => 2016-07-19 08:15
    [type] => 3
)
Array
(
    [start_date] => 2016-07-19 08:15
    [end_date] => 2016-07-19 08:30
    [type] => 3
)
Array
(
    [start_date] => 2016-07-20 07:00
    [end_date] => 2016-07-20 07:20
    [type] => 2
)
Array
(
    [start_date] => 2016-07-20 07:20
    [end_date] => 2016-07-20 07:40
    [type] => 2
)
Array
(
    [start_date] => 2016-07-20 07:40
    [end_date] => 2016-07-20 08:00
    [type] => 2
)
Array
(
    [start_date] => 2016-07-20 08:00
    [end_date] => 2016-07-20 08:15
    [type] => 3
)
Array
(
    [start_date] => 2016-07-20 08:15
    [end_date] => 2016-07-20 08:30
    [type] => 3
)
Array
(
    [start_date] => 2016-07-21 07:00
    [end_date] => 2016-07-21 07:20
    [type] => 2
)
Array
(
    [start_date] => 2016-07-21 07:20
    [end_date] => 2016-07-21 07:40
    [type] => 2
)
Array
(
    [start_date] => 2016-07-21 07:40
    [end_date] => 2016-07-21 08:00
    [type] => 2
)
Array
(
    [start_date] => 2016-07-21 08:00
    [end_date] => 2016-07-21 08:15
    [type] => 3
)
Array
(
    [start_date] => 2016-07-21 08:15
    [end_date] => 2016-07-21 08:30
    [type] => 3
)
Array
(
    [start_date] => 2016-07-22 07:00
    [end_date] => 2016-07-22 07:20
    [type] => 2
)
Array
(
    [start_date] => 2016-07-22 07:20
    [end_date] => 2016-07-22 07:40
    [type] => 2
)
Array
(
    [start_date] => 2016-07-22 07:40
    [end_date] => 2016-07-22 08:00
    [type] => 2
)
Array
(
    [start_date] => 2016-07-22 08:00
    [end_date] => 2016-07-22 08:15
    [type] => 3
)
Array
(
    [start_date] => 2016-07-22 08:15
    [end_date] => 2016-07-22 08:30
    [type] => 3
)

我的问题：当我调用我的函数并分配给变量时，似乎该函数没有为变量赋值，但是如果我用print_r检查函数的返回（）显示我们需要的值。我应该跳过的是事情，我需要一个“推动”继续。通过这种方式，使用函数返回声明变量：

$return_value_function = [];
$return_value_function = $this->transformValue($array_values);

变量$ return_value_function不保存函数返回。我的错误在哪里？

Answer 1

您应该从此调用中分配值：

$this->transformValue($value, $level + 1);

变量。像：

$return[$key] = $this->transformValue($value, $level + 1);

每次递归调用此函数时，return语句都会将数据发送回＆amp;没有什么可以保存返回的数据。

<强>解

您可以更改以下功能＆amp;在没有递归的情况下实现相同的输出：

function transformValue($array = []) {
$return = [];
foreach($array as $key => $value) {
    if(is_array($value)) {
        $return = array_merge( $return, $value );
    }
}
return $return;
}

输出结果为：

请注意我的示例数组只包含这两个键。

此输出通过以下代码返回：

$return_value_function = [];
$return_value_function = transformValue($arr);
echo '<pre>';print_r($return_value_function);echo '</pre>';

Answer 2

请参阅以下代码。它会根据您的意愿返回数组。

public function transformValue($array) {        
    foreach($array as $subarray){
        foreach($subarray as $value){
            $finalArray[] = $value;
        }
    }
    return $finalArray;

}

$finalArray= $this->transformValue($array_values);
echo "<pre>";
print_r($finalArray);

PHP - 函数返回和多维数组

2 个答案: