Question

如何拆分字符串以包含分隔符？

假设我有一个像......这样的字符串。

let myString = "apple banana orange grapes"

如果我用过

let separatedString = myString.componentsSeparatedByString(" ")

我的结果数组将是

["apple","banana","orange","grapes"]

我将如何实现

的结果

["apple ","banana ","orange ","grapes"]

Answer 1

array.map可让您处理生成的数组并重新添加空格。

let separatedString = myString
  .componentsSeparatedByString(" ")
  .map { "\($0) " }

最后一行迭代拆分数组中的所有字符串并将它们放在$0中，并返回一个新的字符串，其中添加了一个空格，用作原始字符串的替换。

Answer 2

解决方案

由于您更新了问题，现在看起来您不再需要在最后一个单词上添加新空格。

所以这是我的更新代码

let text = "apple banana orange grapes"

let chunks: [String] = text
    .componentsSeparatedByString(" ")
    .reverse()
    .enumerate()
    .map { $0.element + ( $0.index == 0 ? "" : " ") }
    .reverse()

print(chunks) // ["apple ", "banana ", "orange ", "grapes"]

多个分隔符

感谢 @vadian 提出建议

let text = "apple banana\norange grapes"

let chunks: [String] = text
    .componentsSeparatedByCharactersInSet(.whitespaceAndNewlineCharacterSet())
    .reverse()
    .enumerate()
    .map { $0.element + ( $0.index == 0 ? "" : " ") }
    .reverse()

print(chunks) // ["apple ", "banana ", "orange ", "grapes"]

Answer 3

使用正则表达式的替代方法：

let myString = "apple banana orange grapes"
let pattern = "\\w+\\s?"
let regex  = try! NSRegularExpression(pattern: pattern, options: [])
let matches = regex.matchesInString(myString, options:[], range: NSMakeRange(0, myString.characters.count))
  .map { (myString as NSString).substringWithRange($0.range)}
print(matches) // -> ["apple ", "banana ", "orange ", "grapes"]

Swift：将字符串分隔为字符串数组并附加分隔符

3 个答案:

解决方案

多个分隔符