Question

我正在尝试使用一个类映射我从XML请求获得的响应。但xml响应有所不同，具体取决于某些设置。例如，在响应中，我得到标签“owner”，其中填充了所有者对象的ID。如果我在我的请求中添加一个设置，我将返回完整的所有者数据，如firstname和lastname。现在我想将owner标记映射到String变量或Class，具体取决于响应。

示例：

@XmlAccessorType(XmlAccessType.FIELD)
@XmlRootElement(name = "domain")
public class Response {

    @XmlElement
    private String name;

    @XmlElement(name = "owner")
    private String ownerSimple;

    @XmlElement(name = "owner")
    private Owner ownerComplex;

}

@XmlRootElement(name = "ownerc")
public class OwnerC {

    @XmlElement
    int id;

    @XmlElement
    String fname;

    @XmlElement
    String lname;
}

要映射的XML：

<response>
    <name>Foo</name>
    <owner>1234</owner>  <!-- in this case it's only a id -->
</response>

<response>
    <name>Foo</name>
    <owner>  <!-- in this case it's the owner class -->
        <id>1234</id>
        <fname>Jon</fname>
        <lname>Doe</lname>
    </owner>
</response>

Answer 1

您可以使用@XmlAnyElement(lax=true)来处理此用例。此批注允许您将任何XML解组为Java对象（DOM Node）。在第二步中，可以将Node解组为所需的对象

<强>响应

@XmlAccessorType(XmlAccessType.FIELD)
@XmlRootElement(name = "domain")
public class Response {

    @XmlElement
    private String name;

    @XmlAnyElement(lax=true)
    private Object owner;

    private String ownerSimple;

    @XmlTransient
    private Owner ownerComplex;

<强>所有者

@XmlAccessorType(XmlAccessType.FIELD)
@XmlRootElement(name = "owner")
public class Owner {

    @XmlElement
    int id;

    @XmlElement
    String fname;

    @XmlElement
    String lname;

<强>的Unmarshaller

//Unmarshaller. Step 1 - Decodes Response and set a DOM Node at Owner
//Important. Owner class must not be present in JAXB context, letting next step to decode the object properly. 
//Owner variable at Response class is annotated with @XmlTransient
JAXBContext jaxbContext = JAXBContext.newInstance(Response.class);
Unmarshaller jaxbUnmarshaller = jaxbContext.createUnmarshaller();
Response response = (Response) jaxbUnmarshaller.unmarshal(reader);

//Unmarshaller. Step 2. Convert Node to the suitable Object
//Considering both cases, simple-> String complex -> Owner Object.      
String ownerSimple = ((Node)response.getOwner()).getFirstChild().getNodeValue();
if (ownerSimple != null){
    response.setOwnerSimple(ownerSimple);
} else {
    JAXBContext jaxbContextOwner = JAXBContext.newInstance(Owner.class);
    Unmarshaller  jaxbUnmarshallerOwner = jaxbContextOwner.createUnmarshaller();
    Owner ownerComplex = (Owner) jaxbUnmarshallerOwner.unmarshal((Node)response.getOwner());
    response.setOwnerComplex(ownerComplex);
}

 //Marshaller to system.out. Your object is well mapped in both cases
 Marshaller marshaller = jaxbContext.createMarshaller();
 marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
 marshaller.marshal(rx, System.out);

JAXB将1个XML标记映射到2个变量

1 个答案: