我正在寻找有关如何在SQLite中选择每组第一条记录的选项,其中组的排序是通过复合键进行的。
示例表:
Key_1 | Sort1 | Sort2 | Val_1 | Val_2
-------+-------+-------+-------+-------
1 | 1 | 3 | 0 | 2
1 | 1 | 2 | 2 | 4
1 | 1 | 1 | 4 | 6
1 | 2 | 2 | 6 | 8
1 | 2 | 1 | 8 | 1
2 | 1 | 2 | 0 | 5
2 | 1 | 1 | 1 | 6
2 | 2 | 3 | 2 | 7
2 | 2 | 2 | 3 | 8
2 | 2 | 1 | 4 | 9
目标:
- 按Key_1 ASC, Sort1 ASC, Sort2 DESC
选择数据
- 选择每个唯一Key_1
Key_1 | Sort1 | Sort2 | Val_1 | Val_2
-------+-------+-------+-------+-------
1 | 1 | 3 | 0 | 2
2 | 1 | 2 | 0 | 5
分析功能解决方案......
SELECT
*
FROM
(
SELECT
*,
ROW_NUMBER() OVER (PARTITION BY Key_1
ORDER BY Sort1,
Sort2 DESC
)
AS group_ordinal
FROM
table
)
sorted
WHERE
group_ordinal = 1
费力的ANSI-92方法......
SELECT
table.*
FROM
table
INNER JOIN
(
SELECT
table.Key1, table.Sort1, MAX(table.Sort2) AS Sort2
FROM
table
INNER JOIN
(
SELECT
Key_1, MIN(Sort1)
FROM
table
GROUP BY
Key_1
)
first_Sort1
ON table.Key_1 = first_Sort1.Key_1
AND table.Sort1 = first_Sort1.Sort1
GROUP BY
table.Key1, table.Sort1
)
first_Sort1_last_Sort2
ON table.Key_1 = first_Sort1_last_Sort2.Key_1
AND table.Sort1 = first_Sort1_last_Sort2.Sort1
AND table.Sort2 = first_Sort1_last_Sort2.Sort2
这涉及很多嵌套和自连接。当它只包含两个列时,这很麻烦。
我的实际示例有六个排序列。
我也想避免以下内容,因为 不 (据我所知)保证/确定性......
SELECT
table.*
FROM
table
GROUP BY
table.Key_1
ORDER BY
MIN(table.Sort1),
MAX(table.Sort2)
我还有其他选择吗?
答案 0 :(得分:1)
我相信这可以在SQLite中使用:
select t.*
from table t
where exists (select 1
from (select t2.*
from table t2
where t2.id = t.id
order by t2.sort1 asc, t2.sort2 desc
limit 1
) t2
where t2.sort1 = t.sort1 and t2.sort2 = t.sort2
);
我担心SQLite是否允许嵌套子查询中的相关引用。如果没有,您可以使用=
并将值连接在一起:
select t.*
from table t
where (sort1 || ':' || sort2) =
(select (sort1 || ':' || sort2)
from table t2
where t2.id = t.id
order by sort1 asc, sort2 desc
limit 1
);