Question

Laravel版本4.2

我正在尝试加入多个表并获得结果

我现在有2张桌子

1- projects_info（id - pro_title - pro_address ...）

2- projects_images（id - image - image_id）

我需要从＆＃39; projects_images＆＃39;中提取相关图像。其中image_id = projects_info id

这里我尝试了

这是我的路线

//Projects Route
Route::get('our-projects', 'projectController@currentProjects');
Route::get('project/{id}', 'projectController@viewProject');

//Projects details
//Route::get('project/{id}/about-project', 'projectController@viewProject');
Route::get('project/{id}/about-project', array('as' => 'about-project', 'uses' => 'projectController@viewProject'));
Route::get('project/{id}/project-images', array('as' => 'project-images', 'uses' => 'projectController@viewProjectImages'));

项目模型

    class Projects extends Eloquent implements UserInterface, RemindableInterface
    {

        use UserTrait, RemindableTrait;

        protected $table = 'project_info_arabic';

        public function projectImages()
        {
            return $this->belongsTo('ProjectsImages', 'image_id');
        }

    }

ProjectsImages模型

    class ProjectsImages extends Eloquent implements UserInterface, RemindableInterface
    {
        use UserTrait, RemindableTrait;

        protected $table = 'projects_images';

        public function project()
        {
            return $this->hasOne('Projects', 'id');
        }
    }

这是我的ProjectController

public function currentProjects()
    {
        $pro = Projects::all();
        return View::make('projects.currentProjects', ['pro' => $pro]);
    }

    public function viewProject($id)
    {
        $vp = Projects::find($id);
        return View::make('projects.viewProject', ['viewPro' => $vp]);
    }

    public function viewProjectImages($id)
    {
        $vpi = ProjectsImages::with('project')->get();
        //$vpi = DB::table('projects_images')->select('id', 'image', 'image_id')->get();
        return View::make('projects.projectDetails.projectImages', ['viewProImg' => $vpi]);
    }

以下是我试图将每个页面包含在我的projectsDetails VIEW

中的方法

<div class="mCustomScrollbar">
                                @if(Request::path()=="project/$viewPro->id/about-project")
                                    @include('projects.projectDetails.aboutProject')
                                @elseif(Request::path()=="project/$viewPro->id")
                                    @include('projects.projectDetails.aboutProject')
                                @elseif(Request::path()=="project/$viewPro->id/project-images")
                                    @include('projects.projectDetails.projectImages')
                                @endif
                            </div>

并持续projectImages VIEW

<ul>
            @foreach($viewProImg as $vpi)
                <li class="col-sm-3 col-xs-12">
                    {{ HTML::image("images/projects/$vpi->image", '', array('class'=>'img-responsive')) }}
                </li>
            @endforeach
        </ul>

我的问题

1-我得到的是表中的所有图像，它应该只是与该项目相关的图像

请提供任何帮助

Answer 1

首先，项目有很多图像

public function projectImages()
{
    return $this->hasMany('App\ProjectsImage');
}

..图片属于项目

public function project()
{
    return $this->belongsTo('App\Project', 'project_id');
}

您应该始终参考模型。如果您指的是模型，那么您应该记住以单一形式命名模型的良好实践，如Project和ProjectImage。在Laravel中，他们希望您将表名称命名为复数，并将模型名称命名为单数。因此，如果您没有明确设置表名，它将查找模型名称加上s（ProjectS）。

然后，您可以从Project对象调用projectImages -function。所以在视图中它看起来像这样

@foreach($project->projectImages()->get() as $image)
    // Do what you want with each project images
@endforeach

加入多个表Eloquent

1 个答案: