Question

您好，我正在使用Yii代码显示页码，我只想使用

下一个和上一个按钮如何实现此目的

这是我的代码

public function getNextId()
{
    $record=self::model()->find(array(
            'condition' => 'id>:current_id',
            'order' => 'id ASC',
            'limit' => 1,
            'params'=>array(':current_id'=>$this->id),
    ));
    if($record!==null)
        return $record->id;
    return null;
}
public function getPreviousId()
{
    $record=self::model()->find(array(
            'condition' => 'id<:current_id',
            'order' => 'id DESC',
            'limit' => 1,
            'params'=>array(':current_id'=>$this->id),
    ));
    if($record!==null)
        return $record->id;
    return null;
}

Answer 1

如果您想在网站中添加自定义pageingnation那么这是Controller的基本代码

function actionIndex(){
$query = User::find()->where(['status' => 1]);
$countQuery = clone $query;
$pages = new Pagination(['totalCount' => $countQuery->count()]);
$models = $query->offset($pages->offset)
    ->limit($pages->limit)
    ->all();

return $this->render('index', [
     'models' => $models,
     'pages' => $pages,
]);}

对于视图添加此代码

foreach ($models as $model) { // Do model Code
} echo LinkPager::widget([    'pagination' => $pages,]);

如需了解详情，请获取此链接：http://www.bsourcecode.com/yiiframework2/custom-pagination-in-yiiframework-2-0/

如何在yii中使用next和previous按钮

1 个答案: