提升凤凰eval失败

Question

在尝试从我的代码库中创建一个较小的可重现的案例时，我会到达下面的代码。

对我来说，它无法用g ++ 6.1编译并提升1.60并提升开发效果。

语法和规则使用队列的默认类型和另一位，并且仅指定迭代器和签名。 这是问题吗？

#include <iostream>
#include <boost/spirit/include/qi.hpp>
#include <boost/spirit/include/support_istream_iterator.hpp>
#include <boost/phoenix.hpp>

namespace qis = boost::spirit::qi;
namespace pnx = boost::phoenix;
using qis::_r1; using qis::_r2;
using qis::_val;

template <typename Iterator>
struct G2 : public qis::grammar<Iterator, int(int)>
{
  G2()
  : G2::base_type(start_)
  {
    start_ %= qis::int_
    [
      pnx::if_( _r1 == 5 )
      [
        _val = 6
      ]
      .else_
      [       
        _val = 7
      ]
    ];
  }

  qis::rule<Iterator, int(int)> start_;  
};

template <typename Iterator>
struct G1 : public qis::grammar<Iterator, int(int)>
{
  G1()
    : G1::base_type(start_)
  {
    start_ %= g2_(_r1);
  }

  G2<Iterator> g2_;
  qis::rule<Iterator, int(int)> start_;
};

template <typename Iterator>
struct G : public qis::grammar<Iterator, int()>
{
  G()
    : G::base_type(start_)
  {
    int i;
    start_ %= g1_(i);
  }

  G1<Iterator> g1_;
  qis::rule<Iterator, int()> start_;
};


int main()
{
  G<boost::spirit::istream_iterator> g;

  return 0;
}