Question

我正在使用SQL Server 2008 R2（SP2）数据库。对于客户数据和他的兴趣，我有两个这样的表：

表名：客户

+----+----------+---------+
| Id | Name     | Surname |
+----+----------+---------+
| 1  | Mario    | Rossi   |
+----+----------+---------+
| 2  | Giuseppe | Verdi   |
+----+----------+---------+

表名：客户利益

+------------+----------+
| CustomerId | Interest |
+------------+----------+
| 1          | IT       |
+------------+----------+
| 1          | Football |
+------------+----------+
| 1          | Basket   |
+------------+----------+
| 2          | Basket   |
+------------+----------+
| 2          | Bonsai   |
+------------+----------+

我需要为数据提取创建一个SQL语句。输出结果必须如下：

+----+----------+---------+-----------------------+
| Id | Name     | Surname | Interests             |
+----+----------+---------+-----------------------+
| 1  | Mario    | Rossi   | IT; Football; Basket; |
+----+----------+---------+-----------------------+
| 2  | Giuseppe | Verdi   | Basket; Bonsai;       |
+----+----------+---------+-----------------------+

从本质上讲，我会在一列中将所有客户的兴趣以分号分隔。

我怎样才能获得这个？

谢谢，马可

Answer 1

尝试以下查询

SELECT
    Id,
    Name,
    Surname,
    (
        SELECT 
            CI.Interest + '; '
        FROM                
            CustomerInterests CI
        WHERE 
            CI.CustomerId = C.ID
        FOR XML PATH ('')
    ) AS Interest 
FROM
    Customer C

如何在一列中转换外键值？

1 个答案: