Question

我有一个xml文件来使用xsl-fo模板语言过滤数据。我的XML：

 <root>
<name>shyam</name>
<friend>
    <name>Abc</name>
    <phNo>90909090909</phNo>
    <age>32</age>
    <closefriends>
        <names>test123</names>
    </closefriends>
</friend>
<friend>
    <name>Xyz</name>
    <phNo>32323232323</phNo>
    <age>44</age>
    <closefriends>
        <names>test345</names>
    </closefriends>
</friend>
</root>

我想获取名称和名称值，并将其显示在xsl-fo模板中的某些表格单元格上。

我的XSL-FO模板：

<?xml version="1.0" encoding="iso-8859-1"?>

    <fo:page-sequence master-reference="my-page">
      <fo:flow flow-name="xsl-region-body">
        <fo:block>Hello,
          <xsl:value-of select="name" />!</fo:block>
        <fo:block>
          <fo:table>
            <fo:table-body>
              <fo:table-row>
                <fo:table-cell border="solid 1px black" text-align="center" font-weight="bold">
                  <fo:block>
                    No.
                  </fo:block>
                </fo:table-cell>
                <fo:table-cell border="solid 1px black" text-align="center" font-weight="bold">
                  <fo:block>
                    Name
                  </fo:block>
                </fo:table-cell>
                <fo:table-cell border="solid 1px black" text-align="center" font-weight="bold">
                  <fo:block>
                    Phone Number
                  </fo:block>
                </fo:table-cell>
              </fo:table-row>
              <xsl:for-each select="./friend">
                <xsl:for-each select="./closefriends">
                  <fo:table-row>
                    <fo:table-cell border="solid 1px black" text-align="center">
                      <fo:block>
                        <xsl:value-of select="position()" />
                      </fo:block>
                    </fo:table-cell>
                    <fo:table-cell border="solid 1px black" text-align="center">
                      <fo:block>
                        <xsl:value-of select="name" />
                        <xsl:value-of select="names" />
                      </fo:block>
                    </fo:table-cell>
                    <fo:table-cell border="solid 1px black" text-align="center">
                      <fo:block>
                        <xsl:value-of select="phNo" />
                      </fo:block>
                    </fo:table-cell>
                  </fo:table-row>
                </xsl:for-each>
              </xsl:for-each>
            </fo:table-body>
          </fo:table>
        </fo:block>
      </fo:flow>
    </fo:page-sequence>
  </fo:root>
</xsl:template>

我无法获取名称值，只获得了亲密朋友 - ＆gt;名称。需要在同一个表td上获取名称和名称。

感谢任何帮助..谢谢

Answer 1

嗯，您需要使用<xsl:value-of select="name" />选择父级名称，而不是<xsl:value-of select="../name" />。

如何在单个fo：table-cell上显示xsl-foreach数据？

1 个答案: