Question

我有这个命名查询：

select person from Person person , Citizen citizen 
where person.id = citizen.id ;

我的实体成员具有以下方式

    @Entity
    @Table(name="PERSON")
    public class Person {
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "PERSONID",insertable = false, updatable = false)
    private long personId;
...
   @OneToMany(fetch = FetchType.EAGER, mappedBy = "person", cascade = CascadeType.ALL)
   @Cascade(value = org.hibernate.annotations.CascadeType.ALL)
   @JsonManagedReference
   private Set<Citizen> citizen= new HashSet<Citizen>();
    }

实体公民

@Entity
public class Citizen{
...
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "PERSONID",insertable = false, updatable = false)
    private long personId;

    @ManyToOne(fetch = FetchType.LAZY, cascade = CascadeType.ALL)
    @JoinColumn(name="PERSONID",insertable = false, updatable = false)
    @JsonBackReference
    private Person person;

    private String name;
    private String secondname;
    private String phone;
}

我们的想法是执行命名查询，以检索包含每个人的公民列表的人员对象，只需在响应中使用name属性，不包括phone和secondname属性。有没有办法用HQL或Criteria做到这一点？

来自HQL的条件查询并排除某些列

0 个答案: