Question

我可以使用Muenchian分组从city1或city2或city 3中删除重复项，这是密钥并生成id，如下所示。但是我无法通过循环到所有city1，city2和city3

来删除重复项

以下是xml

<test>
<records>
<city1>Sweden</city1>
<country1>value1<country1>
<town1>value2<town1>
<city2>Paris</city2>
<country2>value1<country2>
<town2>value2<town2>
<city3>London</city3>
<country3>value1<country3>
<town3>value2<town3>
</records>
<records>
<city1>Sweden</city1>
<country1>value1<country1>
<town1>value2<town1>
<city2>Frankfut</city2>
<country2>value1<country2>
<town2>value2<town2>
<city3>NEwYork</city3>
<country3>value1<country3>
<town3>value2<town3>
</records>
<records>
<city1>SFO</city1>
<country1>value1<country1>
<town1>value2<town1>
<city2>London</city2>
<city2>Frankfut</city2>
<country2>value1<country2>
<city3>Frankfut</city3>
<country3>value1<country3>
<town3>value2<town3>
</records>
</test>

输出应为

Row|Add|Sweden|value1|value2
Row|Add|London|value1|value2
Row|Add|NewYork|value1|value2
Row|Add|SFO|value1|value2

用于从city1删除重复项的代码

  <xsl:key name="Keycity"  match="//test/records" use="city1" />
<xsl:for-each select="//records[generate-id(.) = generate-id(key('Keycity', city1))]">
      <xsl:sort select="."/>
      <xsl:variable name="city1" select="."/>

        <Row Action="ADD">
          <xsl:value-of select="city1" />
        </Row>
      </xsl:if>
    </xsl:for-each>

Answer 1

将您的密钥定义为：

<xsl:key name="Keycity" match="city1 | city2 | city3" use="." />

然后做：

<xsl:for-each select="(records/city1 | records/city2 | records/city3)[generate-id(.) = generate-id(key('Keycity', .))]">
    <xsl:sort select="."/>
    <Row Action="ADD">
        <xsl:value-of select="." />
    </Row>
</xsl:for-each>

这假设您处于test根元素的上下文中。

如何在使用xslt时删除重复项

1 个答案: