Question

今年夏天，我一直在为一家公司做一个项目，即使是即将毕业的学生，我仍然非常努力，我一直遇到处理这个小组的问题，并且通过条款订购。

我尝试的任何东西似乎都没有用，到目前为止我所拥有的（语法是suuuuper搞砸了分组/顺序）

SELECT DISTINCT ACT.ROW_ID , ACT.CREATED , MEM.FIRST_NAME , MEM.LAST_NAME , LOC.NAME , COUNT(*) as "number" , CAT.NAME , SER.NAME , EMP.FIRST_NAME , EMP.LAST_NAME , SER.DURATION , ACT.CASH , COS.NAME , ACT.COMMENTS , ACT.TIP FROM
S_ACTIVITY ACT, S_LOCATION LOC, S_CATEGORY CAT, S_EMPLOYEE EMP, S_SERVICE SER, S_COST_CODE COS, S_MEMBER MEM 
WHERE ACT.EMPLOYEE_ID = EMP.ROW_ID AND ACT.SERVICE_ID = SER.ROW_ID AND ACT.CATEGORY_ID = CAT.ROW_ID AND ACT.COST_CODE_ID = COS.ROW_ID AND
ACT.LOCATION_ID = LOC.ROW_ID AND ACT.MEMBER_ID = MEM.ROW_ID 
GROUP BY LOC.NAME
ORDER BY number

这就像在线的其他指南一样，我说我需要某种排序或数量来订购......继承人原来...

SELECT DISTINCT ACT.ROW_ID , ACT.CREATED , MEM.FIRST_NAME , MEM.LAST_NAME , LOC.NAME , CAT.NAME , SER.NAME , EMP.FIRST_NAME , EMP.LAST_NAME , SER.DURATION , ACT.CASH , COS.NAME , ACT.COMMENTS , ACT.TIP FROM
S_ACTIVITY ACT, S_LOCATION LOC, S_CATEGORY CAT, S_EMPLOYEE EMP, S_SERVICE SER, S_COST_CODE COS, S_MEMBER MEM 
WHERE ACT.EMPLOYEE_ID = EMP.ROW_ID AND ACT.SERVICE_ID = SER.ROW_ID AND ACT.CATEGORY_ID = CAT.ROW_ID AND ACT.COST_CODE_ID = COS.ROW_ID AND
ACT.LOCATION_ID = LOC.ROW_ID AND ACT.MEMBER_ID = MEM.ROW_ID 
GROUP BY LOC.NAME
ORDER BY LOC.NAME

感谢您的帮助，非常感谢！：）

Answer 1

这是让你开始的事情，因为你是SO的新手。欢迎，BTW。

我真的会读到Gordon和Maciej的评论，以及关于JOINS的文章。祝你学习顺利。

这只是在语法上对MSSQL是正确的，对你的JOIN有一些假设。它不一定是您正在寻找的结果。

SELECT DISTINCT 
    ACT.ROW_ID, 
    ACT.CREATED, 
    MEM.FIRST_NAME, 
    MEM.LAST_NAME, 
    LOC.NAME,
    COUNT(*) as "number",
    CAT.NAME,
    SER.NAME,
    EMP.FIRST_NAME,
    EMP.LAST_NAME, 
    SER.DURATION,
    ACT.CASH,
    COS.NAME,
    ACT.COMMENTS,
    ACT.TIP 
FROM
    S_ACTIVITY ACT
    INNER JOIN S_LOCATION LOC on ACT.LOCATION_ID = LOC.ROW_ID
    INNER JOIN LOC. S_CATEGORY CAT ON ACT.CATEGORY_ID = CAT.ROW_ID 
    INNER JOIN S_EMPLOYEE EMP ON ACT.EMPLOYEE_ID = EMP.ROW_ID
    INNER JOIN S_SERVICE SER ON ACT.SERVICE_ID = SER.ROW_ID
    INNER JOIN S_COST_CODE COS ON ACT.COST_CODE_ID = COS.ROW_ID
    INNER JOIN S_MEMBER MEM ON ACT.MEMBER_ID = MEM.ROW_ID 
GROUP BY
    --every column that isn't an aggreggate... i.e. everything except COUNT(*). 
    ACT.ROW_ID, 
    ACT.CREATED, 
    MEM.FIRST_NAME, 
    MEM.LAST_NAME, 
    LOC.NAME,
    CAT.NAME,
    SER.NAME,
    EMP.FIRST_NAME,
    EMP.LAST_NAME, 
    SER.DURATION,
    ACT.CASH,
    COS.NAME,
    ACT.COMMENTS,
    ACT.TIP 
ORDER BY 
   --You can't use alias names in GROUP BY or ORDER BY clauses.
    COUNT(*)

Answer 2

明确联接 - 使用它们，它们很棒。这是一个例子：

SELECT DISTINCT ACT.ROW_ID , ACT.CREATED , MEM.FIRST_NAME , MEM.LAST_NAME , LOC.NAME , CAT.NAME , SER.NAME , EMP.FIRST_NAME , EMP.LAST_NAME , SER.DURATION , ACT.CASH , COS.NAME , ACT.COMMENTS , ACT.TIP FROM
S_ACTIVITY ACT, S_LOCATION LOC, S_CATEGORY CAT, S_EMPLOYEE EMP, S_SERVICE SER, S_COST_CODE COS, S_MEMBER MEM 
WHERE ACT.EMPLOYEE_ID = EMP.ROW_ID AND ACT.SERVICE_ID = SER.ROW_ID AND ACT.CATEGORY_ID = CAT.ROW_ID AND ACT.COST_CODE_ID = COS.ROW_ID AND
ACT.LOCATION_ID = LOC.ROW_ID AND ACT.MEMBER_ID = MEM.ROW_ID

变为

SELECT DISTINCT ACT.ROW_ID, ACT.CREATED, MEM.FIRST_NAME, MEM.LAST_NAME, LOC.NAME, 
                CAT.NAME, SER.NAME, EMP.FIRST_NAME, EMP.LAST_NAME, SER.DURATION, 
                ACT.CASH, COS.NAME, ACT.COMMENTS, ACT.TIP 
FROM        S_ACTIVITY ACT  
INNER JOIN  S_LOCATION LOC  ON ACT.LOCATION_ID = LOC.ROW_ID
INNER JOIN  S_CATEGORY CAT  ON ACT.CATEGORY_ID = CAT.ROW_ID
INNER JOIN  S_EMPLOYEE EMP  ON ACT.EMPLOYEE_ID = EMP.ROW_ID
INNER JOIN  S_SERVICE SER   ON ACT.SERVICE_ID = SER.ROW_ID
INNER JOIN  S_COST_CODE COS ON ACT.COST_CODE_ID = COS.ROW_ID
INNER JOIN  S_MEMBER MEM    ON ACT.MEMBER_ID = MEM.ROW_ID

区别 - 区别是SELECT修饰符。它将结果限制为不同的行，与使用GROUP BY all_columns_here相同。如果这是您的目标，那么请完全删除您的GROUP BY，然后您就可以了（请参阅上面的查询）。这导致了最后一点......

分组依据/排序 - 您可以使用GROUP BY或ORDER BY，或两者兼而有之。这些并不需要彼此。此外，如果您有聚合，则只有SQL需要GROUP BY，并且只有特定功能才需要ORDER BY。否则，您可以随意使用它们来满足您的项目要求。

分组/按问题排序MSSQL

2 个答案: