Question

我正在尝试使用简单的邮件系统。它是一个页面，其中包含每个用户发送的最后一条消息。这是我的表

-message

id person1 person2 message  mess_date
1  2       q       hii      2016-07-11 00:00:00.000000
2  q       2       hello    2016-07-10 00:00:00.000000
3  2       q       how r u  2016-07-12 00:00:00.000000
4  2       1       message  2016-07-10 00:00:00.000000
5  q       2       nooooo   2016-07-13 00:00:00.000000

-login

id roll
1  q
2  1
3  2

现在我尝试使用此查询来获取消息 -

suppose $roll="2";
select login.roll as userid, m1.id, m1.message, m1.mess_date 
from message as m1,login 
where (
    (m1.person1=? and login.roll=m1.person2) or 
    (m1.person2=? and login.roll=m1.person1)
) 
group by login.roll 
order by m1.mess_date desc');
$stmt->bind_param('ss', $roll, $roll);

输出有2个结果：

q - hiii - 2016-07-11 00:00:00.000000
1 - message - 2016-07-10 00:00:00.000000

但我希望它由mess_date命令，即

q - nooooo - 2016-07-13 00:00:00.000000
1 - message - 2016-07-10 00:00:00.000000

Answer 1

您的SQL组未正确使用，请尝试以下操作：

假设id总是按时间增长，否则你需要通过max（mess_date）来做：

SELECT msg1.*
FROM (
    SELECT login.roll AS userid, m1.id, m1.message, m1.mess_date 
    FROM message AS m1,login 
    WHERE (
        (m1.person1=? AND login.roll=m1.person2) OR
        (m1.person2=? AND login.roll=m1.person1)
    )
) AS msg1, (
    SELECT msg.userid, max(msg.id) AS maxid
    FROM (
        SELECT login.roll AS userid, m1.id, m1.message, m1.mess_date 
        FROM message AS m1,login 
        WHERE (
            (m1.person1=? AND login.roll=m1.person2) OR
            (m1.person2=? AND login.roll=m1.person1)
        )
    ) AS msg
    GROUP BY userid
) AS msg2
WHERE msg1.userid = msg2.userid
AND msg1.id = msg2.maxid
ORDER BY msg1.mess_date DESC

$stmt->bind_param('ssss', $roll, $roll, $roll, $roll);

按表名desc分组不起作用

1 个答案: