所以我使用自定义Google搜索API来获取数据集中每个名称参数的图片网址。
我想在对Retrofit2的API调用中迭代数据集中的每个名称作为查询参数。
public interface GoogleImageAPI {
@GET("v1?key=MyAPIKEY&cx=MyCustomSearchID&searchType=image&fileType=jpg&imgSize=large&alt=json")
Observable<Photos> loadPhotos(@Query("q") String artistQuery);
}
到目前为止,我已经构建了Retrofit适配器和API实例来返回一个Observable:
public Observable<Photos> getPhotosObservable(String artistName){
Retrofit retrofit = new Retrofit.Builder()
.addCallAdapterFactory(RxJavaCallAdapterFactory.create())
.addConverterFactory(GsonConverterFactory.create())
.baseUrl("https://www.googleapis.com/customsearch/")
.build();
GoogleImageAPI googleImageAPI = retrofit.create(GoogleImageAPI.class);
return googleImageAPI.loadPhotos(artistName.replace(" ","+"));
}
我有一个getPhotos(String name)方法,它创建一个observable并订阅它。我可以使用测试参数iegetPhotos(“rocket”)运行此方法,并返回一个Photos对象,其中包含“火箭”前10个Google照片搜索结果的列表
public void getPhotos(String artistName){
Observable<Photos> photosObservable = mDataManager.getPhotosObservable(artistName);
Subscription subscription = photosObservable.subscribeOn(Schedulers.io())
.observeOn(AndroidSchedulers.mainThread())
.subscribe(new Subscriber<Photos>() {
@Override
public void onCompleted() {
}
@Override
public void onError(Throwable e) {
if(e instanceof HttpException){
HttpException response = (HttpException)e;
Log.i(TAG,"bad response: "+response.code());
}
}
@Override
public void onNext(Photos photos) {
Photos mPhotos = photos;
Log.i(TAG,"size: "+mPhotos);
}
});
}
是否有一种安全/正确的迭代方法,因此调用API 100次而不会耗尽内存或创建100个可观察量?
例如,我可以这样做吗?这看起来非常耗费资源:
for(String name : artistNames){
googleImageAPI.loadPhotos(name.replace(" ","+"))
.subscribeOn(Schedulers.newThread())
.observeOn(AndroidSchedulers.mainThread())
.subscribe(new Subscriber<Github>() {
@Override
public final void onCompleted() {
// do nothing
}
@Override
public final void onError(Throwable e) {
Log.e("GithubDemo", e.getMessage());
}
@Override
public final void onNext(Github response) {
mCardAdapter.addData(response);
}
});
}
编辑(工作示例),生成Photo对象的组合列表:
public void getPhotos(){
mDataManager.getArtists()
.subscribeOn(Schedulers.io())
.subscribe(new Action1<JSONArray>() {
@Override
public void call(JSONArray jsonArray) {
LinkedHashMap<Integer,Artist> artistMap = presentArtists(jsonArray);
Collection<Artist> artists = artistMap.values();
Observable.from(artists)
.map(new Func1<Artist, String>() {
@Override
public String call(Artist artist) {
String artistName;
if(artist.getName().contains("(")){
artistName = artist.getName().substring(0,artist.getName().indexOf("(")-2).replace(" ","+");
}else {
artistName = artist.getName().replace(" ", "+");
}
return artistName;
}
})
.flatMap(new Func1<String, Observable<Photos>>() {
@Override
public Observable<Photos> call(String artistName) {
return mDataManager.getPhotosObservable(artistName);
}
})
.toList()
.subscribeOn(Schedulers.io())
.subscribe(new Subscriber<List<Photos>>() {
@Override
public void onCompleted() {}
@Override
public void onError(Throwable e) {
}
@Override
public void onNext(List<Photos> objects) {
mDataManager.savePhotos(objects);
}
});
}
});
}
答案 0 :(得分:3)
您可以这样做:
Observable.from(artistNames)
.map(name -> name.replace(" ", "+"))
.flatMap(name -> googleImageAPI.loadPhotos(name))
.toList()
.subscribe(new Subscriber<List<Github>>() {
@Override
public final void onCompleted() {
// do nothing
}
@Override
public final void onError(Throwable e) {
Log.e("GithubDemo", e.getMessage());
}
@Override
public final void onNext(List<Github> response) {
mCardAdapter.addAll(response);
}
})
从Observable
创建List
。使用map
运算符替换带有加号的空格。使用flatMap
来调用API。使用toList
创建所有回复的列表。然后,您可以将addAll
的所有响应添加到适配器。