需要一个简单的查询来汇总来自存在3列的表的结果: 订单ID,类别&品牌。
摘要应包含订单ID,不同的类别数量以及属于订单ID的品牌的不同数量。
示例数据:
orderno product brand
1 A Z
1 A X
1 B Y
2 C X
2 B X
3 C X
3 B Y
预期结果:
orderno product brand
1 2 3
2 2 1
3 2 2
答案 0 :(得分:0)
使用DISTINCT
的{{1}}来获得预期结果:
COUNT
使用给定数据执行示例
select orderno, count(distinct product) as product, count(distinct brand) as brand
from testtable
group by orderno
结果:
declare @test1 table (orderno int, product varchar(2), brand varchar(2))
insert into @test1 (orderno, product, brand) values
(1, 'A', 'Z'),
(1, 'A', 'X'),
(1, 'B', 'Y'),
(2, 'C', 'X'),
(2, 'B', 'X'),
(3, 'C', 'X'),
(3, 'B', 'Y');
select orderno, count(distinct product) as product, count(distinct brand) as brand
from @test1
group by orderno
答案 1 :(得分:0)
试试这个,。
#!/bin/sh
username=$1
if [ $(grep -c '^'$username':' /etc/passwd) = 1 ]
then
echo "Warning, please user your AD credentials"
login
fi
输出。,
/etc/pam.d/sshd