我在数据库中有两个表(table_1
和table_2
),每个表都有一个名为Name
的共有列。
我目前正在使用以下代码仅从Name
导入一些数据(status
,table_1
):
/* database section start */
$mysqli = new mysqli("z","z","z","z");
if (mysqli_connect_errno()) {
printf("Connect failed: %s\n", mysqli_connect_error());
exit();
}
/* database section end */
// Choose Relevant items, and turn them into an array
$item_array = array(
'item1',
'item2',
'item3'
);
//implode items, turn into string
$item_implode = join("','", $item_array);
//declare an overall array for result
$product = array();
$result = $mysqli->query("SELECT Name, Status as status from table_1 where Name IN ('$item_implode') ORDER BY FIELD (Name, '$item_implode');");
while($row = $result->fetch_assoc()) {
$product_name = $row['Name'];
// find all keys in $item_array which value is the products
$keys = array_keys($item_array, $product_name);
foreach ($keys as $key) {
// add values for these keys
$product[$key + 1]["Name"] = $row['Name'];
$product[$key + 1]["status"] = $row['status'];//
}
}
如果我还要从table_2
导入数据(例如,名为color
,date_added
的列),我应该向此代码添加什么内容?
我的目标是拥有这些钥匙:
$product[$x]["Name"]
$product[$x]["status"]
$product[$x]["color"]
$product[$x]["date_added"]
编辑:
那个长篇大论并没有回答我的问题。代码与我使用的代码类似,我想知道如何在这个具体案例中准确应用UNION。
我尝试过使用:
$result = $mysqli->query
("(SELECT Name, status as status from table_1 )
UNION
(SELECT Name, color as color from table_2 )
where Name IN ('$item_implode') ORDER BY FIELD (Name, '$item_implode');");
while($row = $result->fetch_assoc()) {
但是我在最后一行遇到致命错误。
EDIT2:
仍然出错:
$result = $mysqli->query
("(SELECT Name, status as statu table_1 where Name IN ('$item_implode') ORDER BY FIELD (Name, '$item_implode') )
UNION (SELECT color from table_2 where Name IN ('$item_implode') ORDER BY FIELD (Name, '$item_implode') );");
while($row = $result->fetch_assoc()) {
答案 0 :(得分:1)
$result = $mysqli->query("SELECT table_1.Name, table_1.Status,table_2.color,table_2.date_added from table_1 inner join table_2 on table_1.Name=table_2.Name where table_1.Name IN ('$item_implode') ORDER BY FIELD (Name, '$item_implode');");
答案 1 :(得分:1)
(SELECT Name, Status as status FROM table_1 t1)
UNION
(SELECT color, date_added FROM table_2 t2)
答案 2 :(得分:0)
更改您的查询,并尝试使用:INNER JOIN table_2
我无法为您查询,因为我没有您的数据......
答案 3 :(得分:0)
使用联接构建查询。
$query="SELECT t1.Name, t1.Status as status, t2.color, t2.date_added) from "
."table_1 t1 "
."LEFT JOIN table_2 t2 ON t2.Name "
."where t1.Name IN ('$item_implode') "
."AND t2.Name = t1.Name "
."ORDER BY FIELD (t1.Name, '$item_implode');";