Question

我正在开发一个Windows窗体应用程序。为某些服务创建UI。发生的事情是当我创建应用程序时，有一些按钮，单击一下就可以获取并设置值，但是在完成代码之后，所有这些按钮都会响应双击。当我们应用一些断点和测试时，仅在单击中获取和设置值，但在运行时它需要双击。有人可以帮忙吗？

Answer 1

以下是来自MSDN的完整Article，关于如何仅使用单击而不是双击。此外，它还说明了如何处理事件并区分单击和双击。

本文使用布尔值和计时器来做到这一点。如果您有多个按钮，则可能需要使用hive> select max(IT1C1+IT1C2) from iitest1; Query ID = root_20160713172448_09ccc9e6-c70d-4e56-b428-e511f62db9a6 Total jobs = 1 Launching Job 1 out of 1 Number of reduce tasks determined at compile time: 1 In order to change the average load for a reducer (in bytes): set hive.exec.reducers.bytes.per.reducer=<number> In order to limit the maximum number of reducers: set hive.exec.reducers.max=<number> In order to set a constant number of reducers: set mapreduce.job.reduces=<number> Starting Job = job_1468423564920_0003, Tracking URL = http://sandbox.hortonworks.com:8088/proxy/application_1468423564920_0003/ Kill Command = /usr/hdp/2.3.0.0-2557/hadoop/bin/hadoop job -kill job_1468423564920_0003 Interrupting... Be patient, this might take some time. Press Ctrl+C again to kill JVM killing job with: job_1468423564920_0003 Hadoop job information for Stage-1: number of mappers: 0; number of reducers: 0 2016-07-13 17:49:56,510 Stage-1 map = 0%, reduce = 0% Ended Job = job_1468423564920_0003 with errors Error during job, obtaining debugging information... FAILED: Execution Error, return code 2 from org.apache.hadoop.hive.ql.exec.mr.MapRedTask MapReduce Jobs Launched: Stage-Stage-1: HDFS Read: 0 HDFS Write: 0 FAIL Total MapReduce CPU Time Spent: 0 msec hive> exit > ;。希望它有所帮助。

以下是链接因某些原因而被删除或删除的示例：

处理MouseDown事件并确定位置和时间跨度使用适当的SystemInformation属性和之间的点击之间定时器组件。根据是否执行适当的操作点击或双击发生。以下代码示例演示如何做到这一点。

Dictionary<Button, boolean>

Answer 2

您可以使用计时器简单地识别单击和双击。这是示例

class Form1 : Form
{
       Timer timer;

       public Form1()
       {
            InitializeComponent();
            timer = new Timer();
            timer.Interval = 500;
            timer.Tick += new EventHandler(Timer_Tick);
       }
       private void App_MouseDown(object sender, MouseEventArgs e)
        {
            if (e.Clicks == 1)
            {
                timer.Start();
            }
            else
            {
                timer.Stop();
                doubleClick();
            }
        }

        private void Timer_Tick(object sender, EventArgs e)
        {
            timer.Stop();
            singleClick();
        }

        //Single click 
        public void singleClick()
        {
           MessageBox.Show("Single Click.");
        }

        //Double click 
        public void doubleClick()
        {
           MessageBox.Show("Double Click.");
        }
}

Answer 3

我通过编写一段代码得到了解决方案。只需在第一次点击时激活按钮。

bool firstClick = true; {if（firstClick）{button.select（）; //激活按钮}}

感谢大家的回复。

C＃。当我需要单击时如何避免双击

3 个答案: