Question

有没有更好的方法从二进制字符串中获取bit [] 例如
假设我想要从索引= 3到长度（len = 5）的位 BinaryString = 100 11000 000000010000111110000001
预期结果= 11000左

这是我到目前为止所做的。

方法1

    public void getBits1(){
    int idx = 3;
    int len = 5;
    String binary = new BigInteger("98010F81", 16).toString(2);
    char[] bits = binary.toCharArray();
    String result = "";

    //check here: to make sure len is not out of bounds
    if(len + idx > binary.length())
        return; //error

    for(int i=0; i<len; i++){
        result = result + bits[idx];
        idx++;
    }

    //original
    System.out.println(binary);
    //result
    System.out.println(result);
}

方法2

    public void getBits2(){
    int idx = 3;
    int len = 5;
    String binary = new BigInteger("98010F81", 16).toString(2);
    String result = binary.substring(idx, len+idx);

    //original
    System.out.println(binary);
    //result
    System.out.println(result);
}

Answer 1

我认为value.substring（int，int）没问题。

从二进制字符串

1 个答案: