所有
虽然这与另一个post类似,但该帖子(并未说明如何执行此操作(如果可以),而不实例化对象。此外,如果没有成功,我尝试了多个主题的变体:
class[method](arg)
class[method].call(arg)
method.apply(class, arg)
我是Flex新手,但在C#和Java中都使用了Reflection。顺便说一下,我试图在Flex中工作的代码在这两种语言中都有镜像,并按预期工作。
感谢任何帮助, 谢谢, 托德
无效的Flex代码:
private function ipMethodTester( ipMethodName:String,
shouldPass:Array, shouldFail:Array):void
{
var message:String;
var entry:String;
for each(entry in shouldPass)
{
message = ipMethodName + ": " + entry + " should pass";
try
{
Assert.assertTrue(message,
FieldValidator[ipMethodName](entry));
}
catch(e:Error)
{
Assert.fail(e.message + " " + message);
}
}
for each(entry in shouldFail)
{
message = ipMethodName + ": " + entry + " should fail";
try
{
Assert.assertFalse(message,
FieldValidator[ipMethodName](entry));
}
catch(e:Error)
{
Assert.fail(e.message + " " + message);
}
}
}
Java代码:
private void ipMethodTester(final String ipMethodName,
final String[] shouldPass, final String[] shouldFail)
{
Method method;
try
{
method = InetUtil.class.getDeclaredMethod(ipMethodName, String.class);
method.setAccessible(true);
for(String entry : shouldPass)
{
Object[] invokeArgs = { entry };
boolean passed = (Boolean)method.invoke(null, invokeArgs);
assertTrue(ipMethodName + ": " + entry + " should pass", passed);
}
for(String entry : shouldFail)
{
Object[] invokeArgs = { entry };
boolean passed = (Boolean)method.invoke(null, invokeArgs);
assertFalse(ipMethodName + ": " + entry + " should fail", passed);
}
}
catch (final Exception e)
{
fail(e.getClass().toString());
}
}
C#代码:
private void ipMethodTester(string ipMethodName, string[] shouldPass, string[] shouldFail)
{
Type type = typeof (ValidateUtil);
BindingFlags bindingFlags = BindingFlags.InvokeMethod
| BindingFlags.Public | BindingFlags.NonPublic | BindingFlags.Static;
MethodInfo method = type.GetMethod(ipMethodName, bindingFlags);
foreach(string entry in shouldPass)
{
object[] invokeArgs = { entry };
bool passed = (bool)method.Invoke(null, invokeArgs);
Assert.IsTrue(passed, ipMethodName + ": " + entry + " should pass");
}
foreach(string entry in shouldFail)
{
object[] invokeArgs = { entry };
bool passed = (bool)method.Invoke(null, invokeArgs);
Assert.IsFalse(passed, ipMethodName + ": " + entry + " should fail");
}
}
答案 0 :(得分:1)
这对我有用:
MyClass['myMethod']('arg1','arg2');
这也有效:
MyClass['myMethod'].call(MyClass, 'arg1', 'arg2');
注意:'call'方法的第一个参数(本例中为MyClass)只是指定在函数内部使用'this'关键字时引用的对象。