Question

说我们有一个对象：

   var db = [
        {Id: "201" , Player: "Jon",price: "3.99", loc: "NJ" },
        {Id: "202", Player: "Sam",price: "4.22", loc: "PA" },
        {Id: "203" ,Player: "Sam",price: "4.22", loc: "NY" },
        {Id: "204", Player: "Bill",price: "3.22", loc: "TX" },
        {Id: "205" ,Player: "Dave",price: "3.99", loc: "WA" },
        {Id: "206" ,Player: "Dave",price: "3.99", loc: "WI" },
];

202,203,205,206对于玩家和价格具有相似的值，但我只需要一个id用于相似的值，即输出应为202,205。

Answer 1

您可以先使用reduce()返回包含每个Player|price组合计数的对象。然后，您可以使用另一个减少，并检查Player|price数量是否> 1。如果是，则将对象id添加到数组。

var db = [
   {Id: "201" ,Player: "Jon",price: "3.99", loc: "NJ" },
   {Id: "202", Player: "Sam",price: "4.22", loc: "PA" },
   {Id: "203" ,Player: "Sam",price: "4.22", loc: "NY" },
   {Id: "204", Player: "Bill",price: "3.22", loc: "TX" },
   {Id: "205" ,Player: "Dave",price: "3.99", loc: "WA" },
   {Id: "206" ,Player: "Dave",price: "3.99", loc: "WI" },
];

var obj = db.reduce(function(o, e) {
  o[e.Player + '|' + e.price] = (o[e.Player + '|' + e.price] || 0) + 1;
    return o;
}, {});

var result = db.reduce(function(r, e) {
  if(obj[e.Player + '|' + e.price] > 1) r.push(e.Id);
    return r;
}, []);

console.log(result)

Answer 2

var result = []; 

db.forEach(function(item, index){  
   db.forEach(function(item2, index2){ 
      if (index == index2) return;
      if (item.Player == item2.Player && item.price == item2.price) {   
         if(result.indexOf(item.Id) < 0){  
           result.push(item.Id);
         }
         if(result.indexOf(item2.Id) < 0){
           result.push(item2.Id);
         }
      }
   });
});

console.log(result); // [202,203,205,206]

我并不是说这是有史以来最正确的决定，但它足够有效且可以理解。您可以通过以下评论自行检查：

https://codepen.io/anon/pen/vKWZKx

Answer 3

您可以通过简单循环获取ID。

var db = [
        {Id: "201" , Player: "Jon",price: "3.99", loc: "NJ" },
        {Id: "202", Player: "Sam",price: "4.22", loc: "PA" },
        {Id: "203" ,Player: "Sam",price: "4.22", loc: "NY" },
        {Id: "204", Player: "Bill",price: "3.22", loc: "TX" },
        {Id: "205" ,Player: "Dave",price: "3.99", loc: "WA" },
        {Id: "206" ,Player: "Dave",price: "3.99", loc: "WI" },
];

for(var i = 0; i < db.length; i++){
  var obj = db[i];
  console.log('Id: ', obj.Id);
}

Javascript：如何获取多个重复记录的唯一ID

3 个答案: