如何将选定的参数传递给python构造函数

Question

我有一个这样的初始化器：

def __init__(self, options=None, rinse=True, algorithm="foo"):
   if options is not None:
      self.options = options
   else: 
      self.create_default()

   if (rinse==False): #would mean rinse parameter was passed
      self.options.rinse = rinse
   if (algorithm!="foo"): #would mean algorithm parameter was passed
      self.options.algorithm = algorithm

我希望能够通过多种方式调用上述内容。以下是一些例子：

a = MyClass() #nothing was passed
a = MyClass(rinse: False) #only rinse parameter was passed
a = MyClass(algorithm: "bar") #only algorithm parameter was passed
a = MyClass(options, rinse, algorithm) #pass all three arguments

问题

如何构建此初始化程序，以便我可以传递选择性参数。

Answer 1

如果您愿意更改示例以使用等号而不是冒号，那么__init__应该可以正常工作：

a = MyClass() #nothing was passed
a = MyClass(rinse= False) #only rinse parameter was passed
a = MyClass(algorithm= "bar") #only algorithm parameter was passed
a = MyClass(options, rinse, algorithm) #pass all three arguments