我在模式匹配时收到一个好奇的警告,但只有当OverloadedStrings被启用时...
$ ghci -Wall
GHCi, version 6.12.1: http://www.haskell.org/ghc/ :? for help
Loading package ghc-prim ... linking ... done.
Loading package integer-gmp ... linking ... done.
Loading package base ... linking ... done.
Prelude> let f x = case (x :: [String]) of {[""] -> "root"; ["product", _] -> "product"; _ -> "unknown"}
Prelude> :q
Leaving GHCi.
$ ghci -Wall -XOverloadedStrings
GHCi, version 6.12.1: http://www.haskell.org/ghc/ :? for help
Loading package ghc-prim ... linking ... done.
Loading package integer-gmp ... linking ... done.
Loading package base ... linking ... done.
Prelude> let f x = case (x :: [String]) of {[""] -> "root"; ["product", _] -> "product"; _ -> "unknown"}
<interactive>:1:10:
Warning: Pattern match(es) are overlapped
In a case alternative: [""] -> ...
Prelude> let g x = case (x :: [String]) of {[] -> "root"; ["product", _] -> "product"; _ -> "unknown"}
Prelude> let h x = case (x :: [String]) of {["oops"] -> "root"; ["product", _] -> "product"; _ -> "unknown"}
Prelude> :q
Leaving GHCi.
我不明白为什么我会收到带有OverloadedStrings的f
警告,特别是因为没有OverloadedStrings我没有得到f
的警告,也没有收到g
的警告{1}}或h
,仅在第一种模式中与f
不同(在所有情况下仅匹配一个特定值)。
假设这不是GHC中的错误,我错过了什么?
答案 0 :(得分:4)
这是一个稍微简单的例子,它在GHC 6.12.3中显示了同样的问题:
f :: String -> Bool
f "" = True
f "a" = False
g :: String -> Bool
g "" = True
g "aa" = False
只有g
获得与-XOverloadedStrings
的重叠警告。我认为这必须是一个错误。
答案 1 :(得分:2)
编辑:基本上你想要这个(在匹配从(IsString b) => b
转换回[Char]
之后,但匹配是在一致的类型中完成的):
f :: [String] -> String
f = matchf
matchf :: (Show b, IsString a, Eq a, IsString b) => [a] -> b
matchf x = case x of [""] -> "root"; ["product", _] -> "product"; _ -> "unknown"
否则GHC会警告将"" :: String
与"" :: (Data.String.IsString t) => t
(字面值)匹配。如果文字""
正确默认为String,那么找出原因(可能是错误?)会很有趣:
Prelude> show ("" :: (Data.String.IsString t) => t)
<interactive>:1:0:
Warning: Defaulting the following constraint(s) to type `String'
您的字符串必须派生Eq进行模式匹配才能使用-XOverloadedStrings。 String仍然只是带有-XOverloadedStrings的[Char],但字符串文字不是。
在不触发警告的情况下执行此操作的另一种方法:
test.hs:
import GHC.Exts(IsString(..))
newtype OString = OString String deriving (Eq, Show)
instance IsString OString where fromString = OString
f :: [OString] -> OString
f x = case (x :: [OString]) of {[""] -> "root"; ["product", _] -> "product"; _ -> "unknown"}
运行它:
$ ghci -Wall -XOverloadedStrings
GHCi, version 6.12.1: http://www.haskell.org/ghc/ :? for help
Loading package ghc-prim ... linking ... done.
Loading package integer-gmp ... linking ... done.
Loading package base ... linking ... done.
Prelude> :l test.hs
[1 of 1] Compiling Main ( test.hs, interpreted )
Ok, modules loaded: Main.
*Main> f []
OString "unknown"
*Main> f [""]
OString "root"
*Main> f ["product"]
OString "unknown"
*Main> f ["product", "x"]
OString "product"