Question

我试图在我的Datepicker中设置最大和最小小时。我设法设置最小值，但无法解决最大值。以下是我到目前为止的情况：

    let startHour: Int = 8
    let endHour: Int = 22
    let date1: NSDate = NSDate()
    let gregorian: NSCalendar = NSCalendar(calendarIdentifier: NSCalendarIdentifierGregorian)!
    let components: NSDateComponents = gregorian.components(([.Day, .Month, .Year, .Hour, .Minute]), fromDate: date1)

    if components.hour >= 22 && components.hour < 8 {
        components.hour = startHour
        components.minute = 0
        components.second = 0
    }

    let startDate: NSDate = gregorian.dateFromComponents(components)!

    components.hour = endHour
    components.minute = 0

    let endDate: NSDate = gregorian.dateFromComponents(components)!

    picker.datePickerMode = .DateAndTime
    picker.minimumDate = startDate
    picker.maximumDate = endDate
    picker.setDate(startDate, animated: true)

有没有办法忽略方法.maximumDate（现在是我当前的日期）中的当前日期和月份？它将我选择的未来日期设置回当前日期，并仅检查设置为上午8点至晚上10点的小时间隔。我希望DatePicker能够为每个未来日的上午8点到晚上10点开始提取时间，而不仅仅是当天。

Answer 1

删除picker.maximumDate = endDate并编写自己的自定义验证方法。

// Call datePickerChanged method when the picker finishes rotating
picker.addTarget(self, action: #selector(datePickerChanged(_:)), forControlEvents: .ValueChanged)

func datePickerChanged(picker: UIDatePicker) {
    let selectedDate = picker.date
    // 1) if selectedDate's hour > than your endHour (10pm)
    // 2) create yourNewDate with endHour = 10pm
    // 3) set new date with animation
    picker.setDate(yourNewDate, animated: true)
}

SWIFT 2.2 DatePicker中的最小和最大HOUR

1 个答案: