我正在尝试将具有相同结构但不同数据的两个XML合并为一个。
我收到此错误:A node of type Document cannot be added to content.
以下是我的代码
var productElements =
testGroupProvider.GetTestGroup().ProductTests.Select(
productTest => new XElement(xNamespace + "Product",
new XElement(xNamespace + "ExternalId", productTest.ProductNameKey),
new XElement(xNamespace + "Name", testGroupProvider.GetProductName(productTest)),
new XElement(xNamespace + "ImageUrl", ChoiceBaseHostName + GetProductImageUrl(productTest, TargetDatabase))));
var root = new XDocument(
new XElement(xNamespace + "Feed",
new XAttribute("xmlns", xNamespace),
new XAttribute("name", BVFeedsName),
new XAttribute("incremental", "true"),
new XAttribute("extractDate", DateTime.Now.ToString("o")),
new XElement(xNamespace + "Categories",
new XElement(xNamespace + "Category",
new XElement(xNamespace + "ExternalId", testGroupProvider.GetProductGroup().Id),
new XElement(xNamespace + "Name", testGroupProvider.GetProductGroup().Name),
testGroupProvider.GetTestGroup().Name),
new XElement(xNamespace + "Products", productElements)));
var filePath = @"D:\testXML\test.xml";
XElement xml = XElement.Load(filePath);
xml.Add(root);
xml.Save(filePath);
任何人都可以告诉我我做错了什么。
这是test.xml中的XML结构
<?xml version="1.0" encoding="utf-8"?>
<Feed xmlns="http://www.bazaarvoice.com/xs/PRR/ProductFeed/5.6" name="Choice" incremental="true" extractDate="2016-07-12T15:24:44.5732750+10:00">
<Categories>
<Category>
<ExternalId>{09B3B4FB-F5CF-4522-BE96-4C4B535580C3}</ExternalId>
<Name>Cereal and muesli</Name>
</Category>
</Categories>
<Products>
<Product>
<ExternalId>coles-almond-hazelnut-macadamia-cluster-fusions</ExternalId>
<Name>Coles Almond, Hazelnut & Macadamia Cluster Fusions</Name>
<ImageUrl></ImageUrl>
</Product>
</Products>
</Feed>
第二个XML具有相同的结构,具有不同的产品
<?xml version="1.0" encoding="utf-8"?>
<Feed xmlns="http://www.bazaarvoice.com/xs/PRR/ProductFeed/5.6" name="Choice" incremental="true" extractDate="2016-07-12T15:24:44.5732750+10:00">
<Categories>
<Category>
<ExternalId>{12}</ExternalId>
<Name>cat1</Name>
</Category>
</Categories>
<Products>
<Product>
<ExternalId>Id</ExternalId>
<Name>Ccoles</Name>
<ImageUrl></ImageUrl>
</Product>
</Products>
</Feed>
我想将它们合并如下
<?xml version="1.0" encoding="utf-8"?>
<Feed xmlns="http://www.bazaarvoice.com/xs/PRR/ProductFeed/5.6" name="Choice" incremental="true" extractDate="2016-07-12T15:24:44.5732750+10:00">
<Categories>
<Category>
<ExternalId>{09B3B4FB-F5CF-4522-BE96-4C4B535580C3}</ExternalId>
<Name>Cereal and muesli</Name>
</Category>
<Category>
<ExternalId>{12}</ExternalId>
<Name>cat1</Name>
</Category>
</Categories>
<Products>
<Product>
<ExternalId>coles-almond-hazelnut-macadamia-cluster-fusions</ExternalId>
<Name>Coles Almond, Hazelnut & Macadamia Cluster Fusions</Name>
<ImageUrl></ImageUrl>
</Product>
<Product>
<ExternalId>Id</ExternalId>
<Name>Ccoles</Name>
<ImageUrl></ImageUrl>
</Product>
</Products>
</Feed>
答案 0 :(得分:1)
选择要添加的正确节点并更正要添加的节点。
var filePath = @"D:\testXML\test.xml";
XElement xml = XElement.Load(filePath);
var xmlCategories = xml.Descendants("Categories").First();
var rootCategories = root.Descendants("Category");
xmlCategories.Add(rootCategories);
var xmlProducts = xml.Descendants("Products").First();
var rootProducts = root.Descendants("Product");
xmlProducts.Add(rootProducts);
xml.Save(filePath);
要清楚你正在做什么。
答案 1 :(得分:1)
xml文档必须只有一个根。
使用您附加的文档,可以用以下内容替换xml.Add(root);
(即它将每个节点添加到另一个xml根目录下)
foreach (var child in root.Root.Elements())
{
xml.Element(child.Name.ToString()).Add(child.Nodes());
}
您可以使用Merge
扩展名2 XElement
对上述代码进行概括,使其内容如下所示
foreach (var child in root.Elements())
{
xml.Element(child.Name.ToString()).Merge(child, xNamespace + "ExternalId");
}
定义了扩展名
public static void Merge(this XElement root1, XElement root2, XName element_id)
{
root1.Add(root2.Elements().Except(root1.Elements(), new MyComparer(element_id)));
}
使用xml比较器
public class MyComparer : IEqualityComparer<XElement>
{
private XName _element_id;
public MyComparer(XName element_id)
{
_element_id = element_id;
}
public bool Equals(XElement x, XElement y)
{
return x.Element(_element_id).Value.Equals(y.Element(_element_id).Value);
}
public int GetHashCode(XElement el)
{
return el.Element(_element_id).Value.GetHashCode();
}
}
答案 2 :(得分:1)
Try this
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
using System.Xml;
using System.Xml.Linq;
namespace ConsoleApplication2
{
class Program
{
const string FILENAME1 = @"c:\temp\test1.xml";
const string FILENAME2 = @"c:\temp\test2.xml";
static void Main(string[] args)
{
XDocument doc1 = XDocument.Load(FILENAME1);
XDocument doc2 = XDocument.Load(FILENAME2);
XElement category1 = doc1.Descendants().Where(x => x.Name.LocalName == "Categories").FirstOrDefault();
XElement category2 = doc2.Descendants().Where(x => x.Name.LocalName == "Categories").FirstOrDefault();
category1.Add(category2.Descendants());
XElement product1 = doc1.Descendants().Where(x => x.Name.LocalName == "Products").FirstOrDefault();
XElement product2 = doc2.Descendants().Where(x => x.Name.LocalName == "Products").FirstOrDefault();
product1.Add(product2.Descendants());
}
}
}
答案 3 :(得分:1)
试试这个,抱歉VB
'second is The second XML has the same structure with different products
Dim combined As XElement = New XElement(test) 'create copy of test.xml
combined.<Categories>.LastOrDefault.Add(second.<Categories>.Elements)
combined.<Products>.LastOrDefault.Add(second.<Products>.Elements)
或
'if test can be used to combine then
test.<Categories>.LastOrDefault.Add(second.<Categories>.Elements)
test.<Products>.LastOrDefault.Add(second.<Products>.Elements)
结果是
<Feed name="Choice" incremental="true" extractDate="2016-07-12T15:24:44.5732750+10:00" xmlns="http://www.bazaarvoice.com/xs/PRR/ProductFeed/5.6">
<Categories>
<Category>
<ExternalId>{09B3B4FB-F5CF-4522-BE96-4C4B535580C3}</ExternalId>
<Name>Cereal and muesli</Name>
</Category>
<Category>
<ExternalId>{12}</ExternalId>
<Name>cat1</Name>
</Category>
</Categories>
<Products>
<Product>
<ExternalId>coles-almond-hazelnut-macadamia-cluster-fusions</ExternalId>
<Name>Coles Almond, Hazelnut & Macadamia Cluster Fusions</Name>
<ImageUrl></ImageUrl>
</Product>
<Product>
<ExternalId>Id</ExternalId>
<Name>Ccoles</Name>
<ImageUrl></ImageUrl>
</Product>
</Products>
</Feed>
我使用的测试数据是
Dim test As XElement =
<Feed xmlns="http://www.bazaarvoice.com/xs/PRR/ProductFeed/5.6" name="Choice" incremental="true" extractDate="2016-07-12T15:24:44.5732750+10:00">
<Categories>
<Category>
<ExternalId>{09B3B4FB-F5CF-4522-BE96-4C4B535580C3}</ExternalId>
<Name>Cereal and muesli</Name>
</Category>
</Categories>
<Products>
<Product>
<ExternalId>coles-almond-hazelnut-macadamia-cluster-fusions</ExternalId>
<Name>Coles Almond, Hazelnut & Macadamia Cluster Fusions</Name>
<ImageUrl></ImageUrl>
</Product>
</Products>
</Feed>
Dim second As XElement =
<Feed xmlns="http://www.bazaarvoice.com/xs/PRR/ProductFeed/5.6" name="Choice" incremental="true" extractDate="2016-07-12T15:24:44.5732750+10:00">
<Categories>
<Category>
<ExternalId>{12}</ExternalId>
<Name>cat1</Name>
</Category>
</Categories>
<Products>
<Product>
<ExternalId>Id</ExternalId>
<Name>Ccoles</Name>
<ImageUrl></ImageUrl>
</Product>
</Products>
</Feed>
可以像这样加载XElements
test = XElement.Load("PATH")
second = XElement.Load("second PATH")
并像这样保存
test.Save("PATH")
second.Save("second PATH")
combined.Save("combined PATH")