Question

我有足球（足球）统计数据库。我希望以这种方式展示前三支球队http://footballfacts.ru/turnircats/105166-chempionat-sssr

我在季节中有统计数据表，其中包含了这个名为clubseason的列（以及其他一些在这种情况下不感兴趣的内容）：

idClubSeason
idClub
idSeason
clubPosition

我拥有的下一张桌子适用于俱乐部和季节，每个都有ids（idClub和idSeason）和名字（俱乐部名称和季节）。关系数据库中有三个表。有没有帮助以这种方式在PHP中输出SQL查询？

我的查询是这样的：

    SELECT `jos_igraciDB_club`.`name` , `jos_igraciDB_season`.`idSeason`, `jos_igraciDB_season`.`name`,`jos_clubseason`.`clubPosition`, `jos_igraciDB_club`.`idClub`
FROM `jos_clubseason` 
LEFT JOIN `jos_igraciDB_club` ON `jos_clubseason`.`idClub` = `jos_igraciDB_club`.`idClub` 
LEFT JOIN `jos_igraciDB_season` ON `jos_clubseason`.`idSeason` = `jos_igraciDB_season`.`idSeason` 
ORDER BY `jos_clubseason`.`clubPosition` ASC

Answer 1

我不知道您拥有的确切数据库结构，因此您必须为名称等加入其他表，但这应该足以让您了解如何解决它。 http://sqlfiddle.com/#!9/d22e29/6

SELECT
  cs.season,
  first.club,
  second.club,
  third.club
FROM
  clubseason cs
  INNER JOIN clubseason first  ON first.season  = cs.season AND first.position  = 1 
  INNER JOIN clubseason second ON second.season = cs.season AND second.position = 2 
  INNER JOIN clubseason third  ON third.season  = cs.season AND third.position  = 3 
GROUP BY cs.season

Answer 2

SELECT
  jos_igraciDB_season.name,
  cnf.name, cns.name, cnt.name,
  cs.idSeason,
  first.idClub,
  second.idClub,
  third.idClub
FROM
  jos_clubseason cs
  INNER JOIN jos_clubseason first  ON first.idSeason  = cs.idSeason AND first.clubPosition  = 1
  INNER JOIN jos_clubseason second ON second.idSeason = cs.idSeason AND second.clubPosition = 2
  INNER JOIN jos_clubseason third  ON third.idSeason  = cs.idSeason AND third.clubPosition  = 3
  LEFT JOIN jos_igraciDB_club cnf ON first.idClub = cnf.idClub AND first.clubPosition  = 1
  LEFT JOIN jos_igraciDB_club cns ON second.idClub = cns.idClub AND second.clubPosition  = 2
  LEFT JOIN jos_igraciDB_club cnt ON third.idClub = cnt.idClub AND third.clubPosition  = 3
  LEFT JOIN jos_igraciDB_season ON cs.idSeason = jos_igraciDB_season.idSeason
GROUP BY cs.idSeason

列

2 个答案: