Question

我一直在尝试将数据从我的Android应用程序发送到我的服务器。我使用的服务器是EasyPHP。在我的onCreate（）函数中，我有：

    user_editbox  = (EditText) findViewById(R.id.username_id);
    phone_editbox = (EditText) findViewById(R.id.phonenum_id);
    submit_button = (Button) findViewById(R.id.submit_id);



    submit_button.setOnClickListener( new View.OnClickListener() {

               String username = "Gina";
               String phone_number = "2225550000";
                    public void onClick(View view)
                    {


                        Log.d(TAG, username);
                        Log.d(TAG, phone_number);
                        if(username != null && phone_number != null)
                        {
                            Log.d(TAG, "Inside " + username);
                            Log.d(TAG, "Inside " + phone_number);

                            try {
                                Log.d(TAG, "Entered try");
                                URL url = new URL("http://localhost/Web%20/Practice/Android%20Login/phpserver.php");
                                Log.d(TAG, "URL given");
                                HttpURLConnection urlConnection = (HttpURLConnection) url.openConnection();
                                urlConnection.setRequestMethod("POST");
                                urlConnection.setDoOutput(true);




                                Uri.Builder builder = new Uri.Builder()
                                        .appendQueryParameter("Username ", username)
                                        .appendQueryParameter("PhoneNumber ", phone_number );
                                String query = builder.build().getEncodedQuery();


                                OutputStream os = urlConnection.getOutputStream();    // <--- Problem
                                BufferedWriter writer = new BufferedWriter(new OutputStreamWriter(os, "UTF-8"));
                                writer.write(query);
                                writer.flush();
                                writer.close();
                                os.close();
                                urlConnection.connect();

                            }catch(IOException e)
                            {
                                e.printStackTrace();
                            }

当程序到达

时出现问题

        OutputStream os = urlConnection.getOutputStream();

出现一个说明

的对话框

   Unfortunately, Program has stopped

我试图通过突出显示的代码了解可能导致程序崩溃的原因。服务器似乎运行顺利，PHP脚本如下所示：

有什么想法吗？

logcat的

   07-11 22:17:30.118 2645-2645/com.example.czar.connectingtoserver D/MSG: onCreate
   07-11 22:17:30.120 2645-2645/com.example.czar.connectingtoserver D/MSG: onStart
   07-11 22:17:30.122 2645-2645/com.example.czar.connectingtoserver D/MSG: onResume
   07-11 22:19:24.758 2645-2645/com.example.czar.connectingtoserver D/MSG: Clicked
   07-11 22:19:24.758 2645-2645/com.example.czar.connectingtoserver D/MSG: Gina
   07-11 22:19:24.758 2645-2645/com.example.czar.connectingtoserver D/MSG: 2225550000
   07-11 22:19:24.759 2645-2645/com.example.czar.connectingtoserver D/MSG: Inside Gina
   07-11 22:19:24.759 2645-2645/com.example.czar.connectingtoserver D/MSG: Inside 2225550000
   07-11 22:19:24.759 2645-2645/com.example.czar.connectingtoserver D/MSG: Entered try
   07-11 22:19:24.759 2645-2645/com.example.czar.connectingtoserver D/MSG: URL given
   07-11 22:19:24.759 2645-2645/com.example.czar.connectingtoserver D/MSG: Output set to true
   07-11 22:19:24.759 2645-2645/com.example.czar.connectingtoserver D/MSG: String Encoded

Answer 1

崩溃，因为这里有NetworkOnMainThreadException。您需要将HttpURLConnection的所有工作都放到Thread。

.getOutputStream（）不断崩溃我的应用程序

1 个答案: