Question

这是使用find查找文件的方法，并显示每个文件中的行数

$ find ./ -type f -name "data*.csv" -exec wc -l {} +
   380723 ./data_2016-07-07-10-41-13.csv
   369869 ./data_2016-07-11-10-42-01.csv
   363941 ./data_2016-07-08-10-41-50.csv
   378981 ./data_2016-07-12-10-41-28.csv
  1493514 total

如何按文件名对结果进行排序？以下是我的尝试，但它无效。

$ find ./ -type f -name "data*.csv" -exec wc -l {} + | sort
1493514 total
363941 ./data_2016-07-08-10-41-50.csv
369869 ./data_2016-07-11-10-42-01.csv
378981 ./data_2016-07-12-10-41-28.csv
380723 ./data_2016-07-07-10-41-13.csv
$ find ./ -type f -name "data*.csv" | sort -exec wc -l {} +
sort: invalid option -- 'e'
Try `sort --help' for more information.
$ find ./ -type f -name "data*.csv" -exec sort | wc -l {} +
find: wc: {}missing argument to `-exec'
: No such file or directory
wc: +: No such file or directory
0 total
$

有人可以提供解决方案并纠正我，以便我更好地理解它吗？

EDIT1

来自man sort

  -k, --key=POS1[,POS2]
          start a key at POS1 (origin 1), end it at POS2 (default end of line).  See POS syntax below


   POS is F[.C][OPTS], where F is the field number and C the character position in the field; both are origin 1.  If neither -t nor -b is in effect, characters in a field are counted from the begin‐
   ning of the preceding whitespace.  OPTS is one or more single-letter ordering options, which override global ordering options for that key.  If no key is given, use the entire line as the key.

Answer 1

Ismail建议使用sort -k是正确的。但是，我经常懒得学习（或重新学习）-k的工作原理，所以这是一个廉价的解决方案：

find . -name 'data*.csv' -print0 | sort -z | xargs -0 wc -l

编辑：经过一些实验，我确实弄清了-k的工作原理：

find . -name 'data*.csv' -exec wc -l {} + | sort -k 2

在一个命令

EDIT1

1 个答案: