Question

请你帮我写一个计算字母字符的函数。我此代码的当前输出是这样的：

它包含5个字母字符，其中4个（80.0％）是＆＃39; h＆＃39;

此代码的输出应如下所示：它包含5个字母字符，其中5（100.0％）是＆＃39; h＆＃39;。我想同样对待大写/小写字母

def count(p):
    lows = "abcdefghijklmnopqrstuvwxyz"
    ups =  "ABCDEFGHIJKLMNOPQRSTUVWXYZ"

    numberOfh = 0
    totalChars = 0
    for achar in p:
        if achar in lows or achar in ups:
            totalChars = totalChars + 1
            if achar == 'h':
                numberOfh = numberOfh + 1

    percent_with_h = (numberOfh / totalChars) * 100
    print("It contains", totalChars, "alphabetic characters of which", numberOfh, "(", percent_with_h, "%)", "are 'h'.")


p = "Hhhhh"
count(p)

Answer 1

dataStreamGenerator

我认为应该做你想做的事情

Answer 2

只需将if语句更改为

即可

if achar == 'h' or achar == 'H':

如果你想算上所有＆＃39; h＆＃39;和＆＃39; H＆＃39;。

Answer 3

如果你想计算字符串中任何字母的出现次数，而不仅仅是你可以使用这样的东西，它会返回一个字典，其中包含每个字母作为键，百分比作为值：

    def count_alphas(s):
        s = s.lower()
        alpha_set = set(s)
        alpha_counts = {}

        for x in alpha_set: 
            alpha_counts[x] = s.count(x) / float(len(s)) * 100

        return alpha_counts

    # an example use:
    print(count_alphas('thisissomeexampletext'))

用于计算大写/小写字母的函数

3 个答案: