I have a bash script to call several APIs using HTTPie. I want to capture both the response body AND the HTTP status code.
Here is the best I have managed so far:
rspBody=$( http $URL --check-status --ignore-stdin )
statusCode=$?
Command substitution lets me get the body, and the "--check-status" flag gives me a simplified code (such as 0, 3, 4, etc) corresponding to the code family.
The problem is I need to distinguish between say a 401 and a 404 code, but I only get 4.
Is there a way to get the actual status code without having to do a verbose dump into a file and parse for stuff?
[edit]
This is my workaround in case it helps anyone, but I'd still like a better idea if you have one:
TMP=$(mktemp)
FLUSH_RSP=$( http POST ${CACHE_URL} --check-status --ignore-stdin 2> "$TMP")
STAT_FAMILY=$?
flush_err=$(cat "$TMP" | awk '{
where = match($0, /[0-9]+/)
if (where) {
print substr($0, RSTART, RLENGTH);
}
}' -)
rm "$TMP"
STDERR contains a (usually) 3-line message with the HTTP code in it, so I dump that to a temp file and am still able to capture the response body (from STDOUT) in a variable.
I then parse that temp file looking for a number, but this seems fragile to me.
答案 0 :(得分:4)
此处没有现成的解决方案,但可以通过一些脚本来实现。例如:
STATUS=$(http -hdo ./body httpbin.org/get 2>&1 | grep HTTP/ | cut -d ' ' -f 2)
BODY=$(cat ./body)
rm ./body
echo $STATUS
# 200
echo $BODY
# { "args": {}, "headers": { "Accept": "*/*", "Accept-Encoding": "identity", "Host": "httpbin.org", "User-Agent": "HTTPie/1.0.0-dev" }, "origin": "84.242.118.58", "url": "http://httpbin.org/get" }
命令说明:
http --headers \ # Print out the response headers (they would otherwise be supressed for piped ouput)
--download \ # Enable download mode
--output=./body \ # Save response body to this file
httpbin.org/get 2>&1 \ # Merge STDERR into STDOUT (with --download, console output otherwise goes to STDERR)
| grep HTTP/ \ # Find the Status-Line
| cut -d ' ' -f 2 # Get the status code