Question

我正在使用SQL Server，我的任务是编译一个我们没有从（file1，File2，File3）收到所有3个文件的商店列表。换句话说，每个商店都需要发送这些文件。如果商店没有发送文件，我需要能够识别该商店和缺少的特定文件。

例如，

StoreName|StoreID|NumberReceived|Missing Files
StoreABC   1234    2             File1
SuperStore  4321   1             File1, File2

这是我到目前为止所拥有的。我一直试图找出丢失的文件，并将它们放在一个用逗号分隔的符号列中

SELECT 
ds.StoreName,
StoreID,
COUNT(DISTINCT FileType) as 'NumberReceived'
from ETL.CustomerFileExtractLog cfe
    inner join Final.DimStore ds
        on cfe.StoreID = ds.NABPNumber
where Customer ='ComputerRx'
and TimeStamp >= DATEADD(DAY, -1, GETDATE())
Group by StoreName,
StoreID
having COUNT(DISTINCT FileType) < 3  
order by StoreName

Answer 1

使用STUFF和XML PATH（）我们可以得到逗号分隔，只需根据你的要求修改它就是假设代码

;WITH CTE AS (
    SELECT 
        ds.StoreName,
        StoreID,
         FileType 
        FROM fILETYPE t
        INNER JOIN ETL.CustomerFileExtractLog cfe
            inner join Final.DimStore ds
                on cfe.StoreID = ds.NABPNumber
        where Customer ='ComputerRx'
        and TimeStamp >= DATEADD(DAY, -1, GETDATE())
        Group by StoreName,
        StoreID
        having COUNT(DISTINCT FileType) < 3  )

Select 
    StoreName,
    StoreID,
    COUNT(DISTINCT FileType) as 'NumberReceived',
    STUFF((SELECT ', ' + CAST(Files AS VARCHAR(50)) FileNAmes
FROM CTE  
WHERE StoreID = C.StoreID
FOR XML PATH(''), TYPE)
.value('.','NVARCHAR(MAX)'),1,2,' ')
FROM CTE C

选择SQL select语句中未返回的值

1 个答案: