Question

我使用CURL检索json项目列表。我试图搜索每个项目并仅回显具有搜索词的项目。如果任何项目json字段匹配搜索词我想显示该项目。

        $ch = curl_init();
        curl_setopt($ch, CURLOPT_URL, "https://url.com/api/projects");
        curl_setopt($ch, CURLOPT_RETURNTRANSFER, TRUE);
        curl_setopt($ch, CURLOPT_HEADER, FALSE);
        curl_setopt($ch, CURLOPT_HTTPHEADER, array(
          "Access-Token: CsdujazxcvSq0w"
        ));
        $proj_srch = curl_exec($ch);
        curl_close($ch);
        $json = json_decode($proj_srch, TRUE);

json看起来像这样

(
[success] => 1
[data] => Array
    (
        [0] => Array
            (
                [id] => 1088
                [project_name] => Mission Church
                [project_no] => 1088
                [description] => ries, but also the leap into electronic typesetting, remaining essentially unchanged.
                [institution_name] => Archdio
                [address] => 35 Ptt Street
                [city] => Suaa
                [state_province] => Suaa
                [country] => Fiji
                [country_code] => fj
                [postal_code] => 00000
                [dio_name] => Dio of Suaa
                [featured_image_url] => https://url.org/media/cd51ec97-2684-6ebb-48c8-89d00b9685d3.JPG
            )

        [1] => Array
            (
                [id] => 1100
                [project_name] => Micro-financing
                [project_no] => 1100
                [description] => ries, but also the leap into electronic typesetting, remaining essentially unchanged. 
                [institution_name] => Missions of Africa
                [address] => PO Box 9253
                [city] => Macha
                [state_province] => Macha
                [country] => Kenya
                [country_code] => ke
                [postal_code] => 87199
                [dio_name] => Dio of Macha
                [project_leader] => 55
                [project_leader_name] =>  Bowman
                [status] => published
                [featured_image_url] => https://url.com/media/31bdace8-a384-832c-3976-666f4d2f7bfd.JPG

            )

这是我尝试过没有成功的原因

       if (strpos($json, 'search-term') !== false) {

            foreach ($json['data'] as $key ) {
            echo    $key['project_name'];
            }

        }

Answer 1

您正在将JSON解码为数组，这很好，但是从那时起您需要使用数组函数。例如：

    $ch = curl_init();
    curl_setopt($ch, CURLOPT_URL, "https://url.com/api/projects");
    curl_setopt($ch, CURLOPT_RETURNTRANSFER, TRUE);
    curl_setopt($ch, CURLOPT_HEADER, FALSE);
    curl_setopt($ch, CURLOPT_HTTPHEADER, array(
      "Access-Token: CsdujazxcvSq0w"
    ));
    $proj_srch = curl_exec($ch);
    curl_close($ch);
    $json = json_decode($proj_srch, TRUE);

    $searchTerm = "search-term"; //Or whatever
    $json["data"] = array_filter($json["data"], function ($v) use ($searchTerm) { 
          foreach ($v as $entry) { 
                if (is_string($entry) && strpos($entry,$searchTerm) !== false) { return true; }
          }
          return false;
   });

如何在php中为json数组创建搜索功能

1 个答案: