Question

您如何编写一个sql语句，允许您插入从表单中获取的数据，但是将根据表单上选择的内容在一个tabe或另一个tabe中输入？我知道如何将表单中的数据插入到指定的表中，但我需要能够使用表单来选择要输入数据的表。这是我的表格的副本......

print("<form action="<?=$PHP_SELF?>" enctype="multipart/form-data" method="post">
  <fieldset>
  <legend>Upload Your Motions and Orders Here</legend>
  <table width="80%" border="0">
    <tr>
      <td class="label"> <label for="label">Select Your File:</label>    
    </p></td>
      <td class="input"><input type="hidden" name="MAX_FILE_SIZE" value="30000" />
      <input type="file" name="thefile" value="<? echo $thefile; ?>" accesskey="s" tabindex="10"></td>
    </tr>
    <tr>
      <td class="label"><span class="input">
        <label for="label">Type of File:</label>
      </span></td>
      <td class="input"><select name="field" id="field" value="<? echo $field; ?>" accesskey="t" tabindex="20">
        <option value="Motions">Motions</option>
        <option value="Orders">Orders</option>
        </select>      </td>
    </tr>
    <tr>
      <td class="label"><label for="label">Name of File:</label> </td>
      <td class="input"><label for="type"></label>
      <input type="text" name="name" id="name" value="<? echo $name; ?>" accesskey="n" tabindex="30"></td>
    </tr>
    <tr>
      <td class="label"><label for="label">Date Filed In Court:</label> </td>
      <td class="input"><label for="date"></label>
      <input type="text" name="date" id="date" value="<? echo $date; ?>" accesskey="f" tabindex="40"></td>
    </tr>
    <tr>
      <td class="label"><span class="input">
        <label for="label">Description:</label>
      </span></td>
      <td class="input"><textarea name="description" id="description" cols="30" rows="5" value="<? echo $description; ?>" accesskey="d" tabindex="50"></textarea></td>
    </tr>
    <tr>
      <td class="label">&nbsp;</td>
      <td class="input"><input type="submit" name="submit" value="Upload This File" /></td>
    </tr>
  </table>
  </fieldset>
</form>");`
<form action="<?=$PHP_SELF?>" enctype="multipart/form-data" method="post">
  <fieldset>
  <legend>Upload Your Motions and Orders Here</legend>
  <table width="80%" border="0">
    <tr>
      <td class="label"> <label for="label">Select Your File:</label>    
    </p></td>
      <td class="input"><input type="hidden" name="MAX_FILE_SIZE" value="30000" />
      <input type="file" name="thefile" value="<? echo $thefile; ?>" accesskey="s" tabindex="10"></td>
    </tr>
    <tr>
      <td class="label"><span class="input">
        <label for="label">Type of File:</label>
      </span></td>
      <td class="input"><select name="field" id="field" value="<? echo $field; ?>" accesskey="t" tabindex="20">
        <option value="Motions">Motions</option>
        <option value="Orders">Orders</option>
        </select>      </td>
    </tr>
    <tr>
      <td class="label"><label for="label">Name of File:</label> </td>
      <td class="input"><label for="type"></label>
      <input type="text" name="name" id="name" value="<? echo $name; ?>" accesskey="n" tabindex="30"></td>
    </tr>
    <tr>
      <td class="label"><label for="label">Date Filed In Court:</label> </td>
      <td class="input"><label for="date"></label>
      <input type="text" name="date" id="date" value="<? echo $date; ?>" accesskey="f" tabindex="40"></td>
    </tr>
    <tr>
      <td class="label"><span class="input">
        <label for="label">Description:</label>
      </span></td>
      <td class="input"><textarea name="description" id="description" cols="30" rows="5" value="<? echo $description; ?>" accesskey="d" tabindex="50"></textarea></td>
    </tr>
    <tr>
      <td class="label">&nbsp;</td>
      <td class="input"><input type="submit" name="submit" value="Upload This File" /></td>
    </tr>
  </table>
  </fieldset>
</form>

文件选择字段的类型将决定数据将插入的表格。

Answer 1

我会远离运行动态sql。由于您有已知类型的列表，因此可以根据文件类型将逻辑放在应用层的case语句中选择一个表。另一种选择是使用case语句或一组if语句创建存储过程。这样就不会为插入构造动态sql。

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1 个答案: