Question

我想知道如何实现在我的bash脚本中查找和替换字符串的函数，例如：

#!/bin/bash
if [ $1 -eq 1 ] then
ListToReplace="'Static_value as Column1','Static_value2' as Column2"
Searching which query contain Column1, Column2 , then Somehow replace in queries...
else
do nothing.
fi

query="Select Column1, Column2 from dual"
run query
query2="Select Column3, Column1 from dual"
run query2

让我们假设我们将使用变量1运行脚本，然后query应该看起来：

Select 'Static_value' as Column1,'Static_value2' as Column2  from dual

和query2：

Select Column3, Static_value as Column1 from dual

变量0然后：

Select Column1,Column2  from dual
Select Column3,Column1 from dual

任何提示？感谢

Answer 1

bash中的替换非常简单，但我不确定您为什么需要/想要列表：

#!/bin/bash

query="Select Column1, Column2 from dual"
query2="Select Column3, Column1 from dual"

if [ "${1:-0}" -eq 1 ]; then
    for VAR in query query2; do
        VAL=${!VAR}
        VAL=${VAL/Column1/Static_value as Column1}
        VAL=${VAL/Column2/\'Static_value2\' as Column2}
        eval $VAR=\$VAL
    done
fi

echo run $query
echo run $query2

VAL=${!VAR}按名称读取变量的值。 eval $VAR=\$VAL按名称指定变量的值。（请参阅here for more。）${//}扩展会在值内执行替换。

在bash脚本中查找并替换字符串（来自字符串列表）

1 个答案: