Question

在以下代码中，我的toast未显示。但是，我收到错误，＆＃34; RuntimeException：无法在未调用Looper.prepare（）＆＃34;的线程内创建处理程序。我尝试了Add_City.this和getApplicationContext

try {
                BufferedReader reader = new BufferedReader(
                        new InputStreamReader(is, "iso-8859-1"), 8);
                StringBuilder sb = new StringBuilder();
                while ((line = reader.readLine()) != null) {
                    sb.append(line + "\n");
                }
                is.close();
                result = sb.toString();

                JSONObject json_data = new JSONObject(result);
                code=(json_data.getInt("code"));
                System.out.println(code);
                if(code==1)
                {
                    Toast.makeText(Add_City.this, "Inserted Successfully",Toast.LENGTH_SHORT).show();
                }
                else
                {
                    Toast.makeText(Add_City.this, "Sorry, City Already Available",Toast.LENGTH_LONG).show();
                }
                Log.i("TAG", "Result Retrieved");
            } catch (Exception e) {
                Log.i("TAG", e.toString());
            }

Answer 1

我的猜测是你得到一些异常，或者显示toast的代码没有在主线程上执行。

尝试使用此

runOnUiThread(new Runnable() {
            public void run() {
            //Your toast here
 Toast.makeText(Add_City.this, "Sorry, City Already Available",Toast.LENGTH_LONG).show();
        }
    });

Answer 2

如果你要，

Caused by: java.lang.RuntimeException: Can't create handler inside thread that has not called Looper.prepare()

我相信你在工作线程中呼唤你的祝酒词。例如，AsyncTask的doInBackground（）。只应在UI线程中调用Toast。

试试这个，

new AsyncTask<Integer, Void, Integer>() {
        @Override
        protected Integer doInBackground(Integer[] params) {
            int code = 1; //your logic here.
            return code;
        }

        @Override
        protected void onPostExecute(Integer code) {
            super.onPostExecute(code);
            if(code==1)
            {
                Toast.makeText(Add_City.this, "Inserted Successfully",Toast.LENGTH_SHORT).show();
            }
            else
            {
                Toast.makeText(Add_City.this, "Sorry, City Already Available",Toast.LENGTH_LONG).show();
            }

        }
    }.execute();

为什么我的Toast没有显示

2 个答案: