在Windows

Question

我写了一个命令文件来备份我的数据。有5个这样的文件夹，我必须备份。我没有在系统启动时安排5个作业，而是编写了一个主命令文件，并在主站中调用其余的。请查看我的 master.cmd

@echo OFF

:: backup1
echo Data Backup in Progress for 1
cd C:/Users/backups/1
AntCommand.cmd > logs/%date:~-4,4%%date:~-7,2%%date:~-10,2%.log 2>&1
echo Backup Complete for 1

::backup2
echo Data Backup in Progress for 2
cd C:/Users/backups/2
AntCommand.cmd > logs/%date:~-4,4%%date:~-7,2%%date:~-10,2%.log 2>&1
echo Backup Complete for 2

::backup3
echo Data Backup in Progress for 3
cd C:/Users/backups/3
AntCommand.cmd > logs/%date:~-4,4%%date:~-7,2%%date:~-10,2%.log 2>&1
echo Backup Complete for 3

::backup4
echo Data Backup in Progress for 4
cd C:/Users/backups/4
AntCommand.cmd > logs/%date:~-4,4%%date:~-7,2%%date:~-10,2%.log 2>&1
echo Backup Complete for 4

::backup5
echo Data Backup in Progress for 5
cd C:/Users/backups/5
AntCommand.cmd > logs/%date:~-4,4%%date:~-7,2%%date:~-10,2%.log 2>&1
echo Backup Complete for 5

问题是备份完全正常但仅适用于第一组，在备份第一组后，命令提示符不会移动到下一个命令但只是关闭

请纠正我出错的地方。三江源

Answer 1

使用CALL命令。这将启动一个单独的批次，第一个将继续。

例如：

  

CALL AntCommand.cmd＆gt;日志/％日期：〜-4,4- %%日期：〜-7,2 %%日期：〜-10,2％的.log   2 - ;＆安培; 1