如何为包含多个元素的数组创建for循环?

时间:2016-07-10 22:12:51

标签: javascript arrays for-loop

我是一名学习JavaScript的学生,所以我的知识并不复杂,所以请保持温和。 :)

我得到了:

Add-on

括号中的每个数字代表该季度的数字。我需要给出循环来总结每个区域(加法)和每个区域(在列中添加)的销售额。我理解如何做单项数组。例如:

var region1 = [1540, 1130, 1580, 1105];
var region2 = [2010, 1168, 2305, 4102];

var region3 = [2450, 1847, 2710, 2391];

var region4 = [1845, 1491, 1284, 1575];

var region5 = [2120, 1767, 1599, 3888];

先谢谢你。

5 个答案:

答案 0 :(得分:2)

我不确定这是不是你想要的,但我认为你想要在所有五个地区的总销售额为四分之一;

{
    quarter_1 : 6000,
    quarter_2 : 5000,
    quarter_3 : 7000,
    quarter_4 : 5600
}

答案 1 :(得分:1)

这有两个功能可以做我认为你要问的事情。第一个区域将一个区域作为参数,并输出其数字的总和。

第二个需要两个参数 - 你喜欢它的总和,以及一个包含所有区域的数组。



var region1 = [1540, 1130, 1580, 1105];
var region2 = [2010, 1168, 2305, 4102];
var region3 = [2450, 1847, 2710, 2391];
var region4 = [1845, 1491, 1284, 1575];
var region5 = [2120, 1767, 1599, 3888];

var allRegions = [region1, region2, region3, region4, region5];

function getRegionTotal(region) {
  var total = 0;
  for (var i = 0; i < region.length; i++) {
    total += region[i];
  }
  return total;
}

var region1Total = getRegionTotal(region1);
console.log('Region 1 total:', region1Total);

function getQuarterTotal(quarter, regions) {
  var total = 0;
  for (var i = 0; i < regions.length; i++) {
    // Note that we reduce the quarter variable by one.  This is due to arrays being zero-based.
    total += regions[i][quarter - 1];
  }
  return total;
}
 
var quarter2Total = getQuarterTotal(2, allRegions);
console.log('Quarter 2 total:', quarter2Total);
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答案 2 :(得分:1)

我认为首先应该获得一个数组数组:

var region1 = [1540, 1130, 1580, 1105];
var region2 = [2010, 1168, 2305, 4102];
var region3 = [2450, 1847, 2710, 2391];
var region4 = [1845, 1491, 1284, 1575];
var region5 = [2120, 1767, 1599, 3888];
var rawArr = [];
rawArr.push(region1);
rawArr.push(region2);
rawArr.push(region3);
rawArr.push(region4);
rawArr.push(region5);

然后,您将能够处理添加列和添加列:

var summRegion = rawArr.map((element) => element.reduce((a, b)=> a + b,0));
console.log(summRegion); // [ 5355, 9585, 9398, 6195, 9374 ]
var sumColumns = [0,0,0,0];

for (var i = 0; i < 4; i++)
    rawArr.forEach((element) => {sumColumns[i] += element[i]});

console.log(sumColumns); // [ 9965, 7403, 9478, 13061 ]

答案 3 :(得分:0)

你的意思是这样吗?

$all_posts = $wpdb->get_results( "
SELECT *, pll__(meta_value) as meta_value_pl 
FROM $posts 
LEFT JOIN $postmeta 
ON ( $posts.ID = $postmeta.post_id ) 
WHERE post_type = 'company' AND post_status = 'publish' AND $postmeta.meta_key = '$name' $where_search 
ORDER BY meta_value DESC 
LIMIT $start, $per_page");

之后你将拥有一个像这样结构的对象:

var quarterlyResultsObj = {};
for( var x = 0 ; x < region1.length ; x++ ){
    var thisQuarter = "quarter_" + x;
    var quarterResult = region1[x] + region2[x] + region3[x] + region4[x] + region5[x];  
    quarterlyResultsObj[ thisQuarter ] = quarterResult;
}

答案 4 :(得分:0)

我包括季度和地区的计算。 可以在https://jsfiddle.net/d8hLc9L5/5/中找到工作示例。

var regions = [
    [1540, 1130, 1580, 1105],
    [2010, 1168, 2305, 4102],
    [2450, 1847, 2710, 2391],
    [1845, 1491, 1284, 1575],
    [2120, 1767, 1599, 3888]
  ],
  countRegions = regions.length,
  countQuarter = 4;

function SumQuarter() {
  for (var q = 0; q < countQuarter; q++) {
    var sumQuarter = 0;
    for (var r = 0; r < countRegions; r++) {
      sumQuarter = sumQuarter + regions[r][q];

    }
    console.log('quarter:' + (q + 1) + ' sum: ' + sumQuarter);
  }
}

function SumRegions() {

  for (var r = 0; r < countRegions; r++) {
    var sumRegions = 0;
    for (var q = 0; q < countQuarter; q++) {
      sumRegions += regions[r][q];
    }
    console.log('region:' + (r + 1) + ' sum: ' + sumRegions);

  }
}
SumQuarter();
SumRegions();