我正在从网页中提取数字,我想比较它们,如果 数字超过[前一个,然后在iimDispaly()中显示,否则如果它低于跳过,我在这里做了但是找不到解决方案。
for(var i = 1; i <= 13; i++) {
for(var j = 3; j<=33; j+=3 ) {
iimPlayCode('TAG POS='+j+' TYPE=DIV ATTR=CLASS:"group_row_labeled" EXTRACT=TXT')
var res = iimGetLastExtract();
var result = res.replace(/[а-z]/g, '');
if(j==3) {
var firstRes = result;
}
if(result => firstRes) {
iimDisplay("Highest Number: " + result)
}
}
}
答案 0 :(得分:1)
复制&amp;粘贴以下代码并尝试播放它:
&sql(SELECT *,%ID INTO :tflds()
FROM Sample.Person )
IF SQLCODE=0 {
SET firstflds=14
FOR i=0:1:firstflds {
IF $DATA(tflds(i)) {
WRITE "field ",i," = ",tflds(i),! }
} }
ELSE {WRITE "SQLCODE error=",SQLCODE,! }