Question

我想在F＃中创建一个标签，它使用一个可变变量来返回一个值。不幸的是，F＃将此标签设置为常量值。如果mutable的值发生更改，则标签的值仍然存在。它有点不一致吗？有没有办法让标签（＆＃34; a＆＃34;）依赖于mutable（＆＃34; x＆＃34;）？

let mutable x = 0;

let a = x + 2; // I want not to set a to a constant value
let b two = x + two;

x <- 1;

let c = b 2;

let isConsistent = a = c;


val mutable x : int = 1
val a : int = 2
val b : two:int -> int
val c : int = 3
val isConsistent : bool = false

Answer 1

根据您自己的评论，您希望a成为函数，返回x + 2
直接翻译是：

let mutable x = 0

let a () = x + 2
let b two = x + two

x <- 1

let c = b 2

let isConsistent = a () = c // don't forget to call the function 'a'

(*
val mutable x : int = 1
val a : unit -> int
val b : two:int -> int
val c : int = 3
val isConsistent : bool = true
*)

如何将标签链接到F＃中的可变变量？

1 个答案: