Question

我有这样一张桌子：

Name        Code
-------------------
John        1235
John        1235/11
John        1236/12
Mary        2500
Mary        2500/8
Mary        3600
Mary        3600/9

我想删除代码值包含在另一行中的所有行。在示例中，我想删除这些记录：

Name        Code
-------------------
John        1235
Mary        2500
Mary        3600

Answer 1

这是一种方法：

delete from t
    where exists (select 1
                  from t t2
                  where t2.value like t1.value || '/%'
                 );

如果您不想实际删除记录，只是希望查询不返回它们：

select *
from t
where not exists (select 1
                  from t t2
                  where t2.value like t1.value || '/%'
                 );

这些假设（如示例中），“包含”实际上意味着“从”/“开始。

Answer 2

// you need to know the `length` of `oJdDetails.topics` 
$scope.rates = new Arryay(oJdDetails.topics.length).fill(0); // initialisation of array with `0` value
$scope.displayStars = new Arryay(oJdDetails.topics.length).fill(false);; // initialisation of array with `false` value
$scope.fngetQList = function (topics, index) {
    $scope.displayQList = true;
    $scope.displayStars[index] = true;
    $scope.sTopics = topics;
    $scope.index = index;
    getCandidateInterviewListService.fnGetQList(topics).then(function(response) {
        $scope.aQuestionList = response;
        console.log($scope.aQuestionList);
    });
};

如果字段包含来自另一个记录的值，则删除所有行

2 个答案: