我想从ParentRunner
扩展测试。
我这样做是为了学习,而不是任何特定的场景。
我有下面和下面的课程,也有输出。
我不了解一些事情:
1.为什么" describeChild"反复召唤3次?
2.为什么测试没有运行?(" doOne"和" doTwo")?
不理解这一行:
//结果result = JUnitCore.runClasses(arg0.getClass());
正在执行测试,但我不明白为什么它会这样运作?
3.最重要的是 - 那条线怎么样:
@SuiteClasses({ChildOne.class,ChildTwo.class})?
它对代码的行为没有影响......
非常感谢任何回复的人: - )
套件类:
@RunWith(FamilyRunner.class)
@SuiteClasses({ChildOne.class, ChildTwo.class, ChildThree.class})
public class Suite {
//nothing here
}
亚军类:
public class FamilyRunner extends ParentRunner<ParentClass>{
public FamilyRunner(Class<?> klass) throws InitializationError {
super(klass);
}
@Rule
public TestName name = new TestName();
@Override
protected List<ParentClass> getChildren() {
List<ParentClass> list = new ArrayList<>();
System.out.println("Adding items to list");
list.add(new ChildOne());
list.add(new ChildTwo());
return list;
}
@Override
protected Description describeChild(ParentClass arg0) {
System.out.println("describeChild class: " + arg0.getClass().getSimpleName());
Description desc = Description.createTestDescription(name.getMethodName(),
name.getMethodName(), getClass().getAnnotations());
return desc;
}
@Override
protected void runChild(ParentClass arg0, RunNotifier arg1) {
System.out.println("runChild " + arg0.getClass().getSimpleName());
//Result result = JUnitCore.runClasses(arg0.getClass());
}
}
和
public class ParentClass {
public ParentClass() {
System.out.println("created parent class");
}
}
public class ChildOne extends ParentClass {
public ChildOne() {
System.out.println("created ChildOne class");
}
@Test
public void doOne(){
System.out.println("doOne");
}
}
public class ChildTwo extends ParentClass {
public ChildTwo() {
System.out.println("created ChildTwo class");
}
@Test
public void doTwo(){
System.out.println("doTwo");
}
}
控制台打印:
Adding items to list
created parent class
created ChildOne class
created parent class
created ChildTwo class
describeChild class: ChildOne
describeChild class: ChildTwo
describeChild class: ChildOne
describeChild class: ChildTwo
describeChild class: ChildOne
describeChild class: ChildTwo
runChild ChildOne
runChild ChildTwo
答案 0 :(得分:0)
我可以回答一些问题。
关于@SuiteClasses({ChildOne.class,ChildTwo.class})您没有使用此注释值构建列表。
你可以这样做:
protected List<ParentClass> getChildren() {
Annotation[] runnerAnnotations = super.getRunnerAnnotations();
System.out.println(runnerAnnotations);
Optional<Annotation> suitClass = Arrays.stream(runnerAnnotations)
.filter(a -> a.annotationType().equals(SuiteClasses.class))
.findFirst();
List<ParentClass> list = new ArrayList<>();
if (suitClass.isPresent()) {
SuiteClasses s = (SuiteClasses) suitClass.get();
s.value();
System.out.println("Adding items to list");
for (Class<?> c : s.value()) {
Class<ParentClass> cp = (Class<ParentClass>) c;
try {
list.add(cp.newInstance());
} catch (InstantiationException | IllegalAccessException e) {
e.printStackTrace();
}
}
}
return list;
}
我想你可以在org.junit.runners.Suite来源找到更多信息:http://grepcode.com/file/repo1.maven.org/maven2/junit/junit/4.8.1/org/junit/runners/Suite.java