Question

原始作业是编写一个程序，要求用户输入正整数值。程序应使用循环来获取从1到输入数字的所有整数之和。例如，如果用户输入50，则循环将找到1-50的sume。输入验证：不接受负起始编号。我在下面写了这段代码。

除上述之外：请修改上述代码以反映以下内容：

向用户显示算术函数菜单，允许他们选择Summation，Factorial或Exponential，如下所示：

求和
阶乘
指数
Akkkkkkkkkkkk，请不要再有数学函数了。 ;）

请输入您选择的数学函数（1,2,3或4退出）：

#include <iostream>
#include <iomanip>

using namespace std;

int main()
{
    //Constants for menu choices
    const int SUM = 1,
        FACTORIAL = 2,
        EXPONENTIAL = 3,
        QUIT = 4;

    //Variables
    int choice, input;
    long double num = 1, value = 1, sum = 0;

    do
    {
        //Display menu of arithmetic functions
        cout << "\n\t\tArithmetic Functions\n\n"
            << "1. Summation\n"
            << "2. Factorial\n"
            << "3. Exponential\n"
            << "4. Akkkkkkk No more math functions please ;)\n\n"
            << "Enter your choice: ";
        cin >> choice;

        //validate the menu selection
        while (choice < SUM || choice > QUIT)
        {
            cout << "Please enter a valid menu choice: ";
            cin >> choice;

        }

        //process the user's choice
        if (choice != QUIT)
        {
            //ask user to input a positive integer
            cout << "Please enter any positive integer: ";
            cin >> input;

            while (input < 1) //input validation of positive integer
            {
                cout << "\n" << input << " is not a positive integer.\n";
                cout << "Please enter a positive integer: ";
                cin >> input;
            }

            //Respond to the user's menu selection
            switch (choice)
            {
            case SUM:
                for (int counter = 1; counter <= input; counter++)
                {
                    sum += counter;
                }

                //Display result
                cout << "\nThe sum of numbers 1 - " << input
                    << " " << "is: " << sum << endl;

                sum = 0; // resets variable
                break;


            case FACTORIAL:
                for (int counter = 1; counter <= input; counter++)
                {
                    value *= counter;
                }

                //Display result
                cout << "\nThe value of " << input << " factorial is: ";
                cout << value << endl;

                value = 1; //resets variable
                break;

            case EXPONENTIAL:
                for (int counter = num; counter <= input; counter++)
                {
                    num *= 2;
                }

                //Display result
                cout << "\nThe result is base 2 raised to the power of " << input;
                cout << ": ";
                cout << num << endl;

                num = 1; //resets variable
                break;
            }
        }

        else
        {
            cout << "\nThe program has ended. Goodbye.\n";
        }

    } while (choice != QUIT);
    return 0;
}

现在新程序有这些说明：您将需要至少4个功能：菜单，求和，阶乘和指数。

确保标题栏显示您具有功能以及如何在它们之间传递信息。每个函数都应该有自己的标题块。标题块由每个函数顶部的几行注释组成，用于解释函数的作用。

我被困住了，不知道从哪里开始。如何做任何建议将不胜感激。

使用功能创建菜单

0 个答案: