Android谷歌地图显示贪婪线

时间:2010-09-30 06:47:19

标签: android

我有一个谷歌地图应用程序,它没有显示地图,它只显示行 它没有显示mapview,我也有互联网连接

      And it also genrate the following error
    09-30 12:01:12.934: WARN/Resources(587): Converting to string:             
    TypedValue{t=0x12/d=0x0 a=2 r=0x7f050002}
    09-30 12:01:13.094: WARN/GpsLocationProvider(59): Duplicate add listener for uid     
   10042
   09-30 12:01:13.334: INFO/MapActivity(587): Handling network change 
   notification:CONNECTED

  09-30 12:01:13.334: ERROR/MapActivity(587): Couldn't get connection factory client

Showmap.java         包de.vogella.android.locationapi.maps;

     import android.content.Context;
     import android.location.Location;
     import android.location.LocationListener;
     import android.location.LocationManager;
     import android.os.Bundle;
     import android.widget.RelativeLayout;

    import com.google.android.maps.GeoPoint;
    import com.google.android.maps.MapActivity;
    import com.google.android.maps.MapController;
    import com.google.android.maps.MapView;

     public class ShowMap extends MapActivity {

private MapController mapController;
private MapView mapView;
private LocationManager locationManager;

public void onCreate(Bundle bundle) {
    super.onCreate(bundle);
    setContentView(R.layout.main); // bind the layout to the activity

    // create a map view
    RelativeLayout linearLayout = (RelativeLayout) findViewById(R.id.mainlayout);
    mapView = (MapView) findViewById(R.id.mapview);
    mapView.setBuiltInZoomControls(true);
    mapView.setStreetView(true);
    mapController = mapView.getController();
    mapController.setZoom(14); // Zoon 1 is world view
    locationManager = (LocationManager) getSystemService(Context.LOCATION_SERVICE);
    locationManager.requestLocationUpdates(LocationManager.GPS_PROVIDER, 13,
            14, new GeoUpdateHandler());


}

@Override
protected boolean isRouteDisplayed() {
    return false;
}

public class GeoUpdateHandler implements LocationListener {

    @Override
    public void onLocationChanged(Location location) {
        int lat = (int) (location.getLatitude() * 1E6);
        int lng = (int) (location.getLongitude() * 1E6);
        GeoPoint point = new GeoPoint(lat, lng);
        mapController.animateTo(point); //  mapController.setCenter(point);




    }

    @Override
    public void onProviderDisabled(String provider) {
    }

    @Override
    public void onProviderEnabled(String provider) {

    }

    @Override
    public void onStatusChanged(String provider, int status, Bundle extras) {
    }
}

}

这是我的主要节日 ?xml version =“1.0”encoding =“utf-8”?>                

<application android:icon="@drawable/icon" android:label="@string/app_name">

<uses-library android:name="com.google.android.maps" />
    <activity android:name=".ShowMap"
              android:label="@string/app_name">
        <intent-filter>
            <action android:name="android.intent.action.MAIN" />
            <category android:name="android.intent.category.LAUNCHER" />
        </intent-filter>
    </activity>

<uses-library android:required="true" android:name="com.google.android.maps"></uses-library>

    

和main.xml

           <?xml version="1.0" encoding="utf-8"?>
         <RelativeLayout xmlns:android="http://schemas.android.com/apk/res/android"
         android:id="@+id/mainlayout"
         android:orientation="vertical"
          android:layout_width="fill_parent"
         android:layout_height="fill_parent" >

        <com.google.android.maps.MapView
            android:id="@+id/mapview"
             android:layout_width="fill_parent"
             android:layout_height="fill_parent"
             android:enabled="true"
                android:clickable="true"

             android:apiKey="0cHF-o_cvW1DEz3ocWAyybGqUsg8aUlwKMoyr4A"
             />

2 个答案:

答案 0 :(得分:0)

您是否在AndroidManifest.xml中拥有所需的权限?在我为GPS +地图制作的Android应用中,我有以下内容:

<uses-permission android:name="android.permission.ACCESS_LOCATION" /> 
<uses-permission android:name="android.permission.ACCESS_FINE_LOCATION" />
<uses-permission android:name="android.permission.INTERNET" /> 
<uses-permission android:name="android.permission.ACCESS_GPS" /> 

答案 1 :(得分:0)

这是API密钥的问题。

Here you can do it.

你需要为每个模拟器,设备等生成不同的一个,并为最终版本,你需要将它们与你正在使用的密钥库合并,什么是sux,但没有不同的方式:/。

祝你好运!

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