这些是代码片段。下拉菜单不起作用。尝试了其他方法,但无法成功。我想只从这些代码中解决问题。
<link href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css" rel="stylesheet"/>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.0.3/jquery.min.js"></script>
<div class="row">
<div class="col-lg-12">
<div class="button-group">
<button class="btn btn-default btn-sm dropdown-toggle" type="button" data-toggle="dropdown">Choose an item:
<span class="caret"></span></button>
<ul class="dropdown-menu">
<li><a href="#" class="small" data-value="option1" tabindex="-1"><input type="checkbox" />Chicken Steam Momo</a></li>
<li><a href="#" class="small" data-value="option2" tabindex="-1"><input type="checkbox" />Chicken Fried Momo</a></li>
<li><a href="#" class="small" data-value="option2" tabindex="-1"><input type="checkbox" />Chicken Kothey Momo</a></li>
</ul>
</div>
</div>
</div>
productFlavors {
Prod {
applicationId 'com.test.app'
}
Qa{
applicationId 'com.test.app.qa'
versionName '1.2-QA'
}
Dev{
applicationId 'com.test.app.dev'
versionName '1.2-DEV'
}
}
答案 0 :(得分:1)
您错过了Bootstrap.js
...
var options = [];
$( '.dropdown-menu a' ).on( 'click', function( event ) {
var $target = $( event.currentTarget ),
val = $target.attr( 'data-value' ),
$inp = $target.find( 'input' ),
idx;
if ( ( idx = options.indexOf( val ) ) > -1 ) {
options.splice( idx, 1 );
setTimeout( function() { $inp.prop( 'checked', false ) }, 0);
} else {
options.push( val );
setTimeout( function() { $inp.prop( 'checked', true ) }, 0);
}
$( event.target ).blur();
console.log( options );
return false;
});
<link href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/css/bootstrap.min.css" rel="stylesheet"/>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.0.3/jquery.min.js"></script>
<script src="http://maxcdn.bootstrapcdn.com/bootstrap/3.3.6/js/bootstrap.min.js"></script>
<div class="row">
<div class="col-lg-12">
<div class="button-group">
<button class="btn btn-default btn-sm dropdown-toggle" type="button" data-toggle="dropdown">Choose an item:
<span class="caret"></span></button>
<ul class="dropdown-menu">
<li><a href="#" class="small" data-value="option1" tabindex="-1"><input type="checkbox" />Chicken Steam Momo</a></li>
<li><a href="#" class="small" data-value="option2" tabindex="-1"><input type="checkbox" />Chicken Fried Momo</a></li>
<li><a href="#" class="small" data-value="option2" tabindex="-1"><input type="checkbox" />Chicken Kothey Momo</a></li>
</ul>
</div>
</div>
</div>
答案 1 :(得分:0)
根据错误,您似乎还没有将jQuery导入到您的html中。