Question

我尝试比较两次，我parse'em然后我使用compareTo像：

        Date one = new Date();
        Date two = new Date();

        SimpleDateFormat sdf = new SimpleDateFormat("hh:mm", java.util.Locale.getDefault());

try {
                        two = sdf.parse("12:33");
                    } catch (ParseException e1) {
                        e1.printStackTrace();
                    }

                    if (one.compareTo(two) < 0) {
                         //do this
                    }

当它不起作用时:(条件总是1）我试着用这个：

Date one = new Date();
        Date two = new Date();  
        boolean check = false;
        SimpleDateFormat sdf = new SimpleDateFormat("hh:mm", java.util.Locale.getDefault());
try {
                        two = sdf.parse("12:22");
                        check = two.after(one);
                    } catch (ParseException e1) {
                        e1.printStackTrace();
                    }

                    if(check)
                      // do this
                    }

第二个代码根本不起作用，我的崩溃

Answer 1

您可以使用compareTo。 compareTo（）方法在接口 java.lang.Comparable 中定义。

Calendar c = Calendar.getInstance();
SimpleDateFormat sdf = new SimpleDateFormat("HH:mm");
String getCurrentTime = sdf.format(c.getTime());
String getTestTime="09:45";

if (getCurrentTime .compareTo(getTestTime) < 0)

{
   // Do your staff
 Log.d("Return","getTestTime less than getCurrentTime "); 
}
else
{
 Log.d("Return","getTestTime older than getCurrentTime "); 
}

Answer 2

更改SimpleDateFormat，如下所示......

SimpleDateFormat sdf = new SimpleDateFormat("HH:mm");

以下是模式：

H   Hour in day (0-23)  Number  0
k   Hour in day (1-24)  Number  24
K   Hour in am/pm (0-11)    Number  0
h   Hour in am/pm (1-12)    Number  12

这将有效....

UpDate：

看看它的工作方式..

SimpleDateFormat sdf = new SimpleDateFormat("HH:mm");
    Date inTime = sdf.parse("11:00");
    Date outTime = sdf.parse("10:00");

    if(inTime.compareTo(outTime) > 0){
    Toast.makeText(this, "Out time should be greater than In time", Toast.LENGTH_SHORT).show();
    }

比较两次格式HH：MM java-android

2 个答案: