辅助监视器上的显示窗口

Question

我想在辅助监视器上显示一个窗口，如下所示：

Queue<string> itemQueue = new Queue<string>();

MonitorWindow monitor = new MonitorWindow(itemQueue);

var secondaryScreen = System.Windows.Forms.Screen.AllScreens.Where(s => !s.Primary)
                                                            .FirstOrDefault();

if (secondaryScreen != null)
{
     monitor.WindowStartupLocation = WindowStartupLocation.Manual;
     var workingArea = secondaryScreen.WorkingArea;
     monitor.Left = workingArea.Left;
     monitor.Top = workingArea.Top;
     monitor.Width = workingArea.Width;
     monitor.Height = workingArea.Height;
     monitor.Show();

}

属性具有正确的值，但这会使主监视器上的Window最大化。你能救我吗？

Answer 1

好的，我已经修复了问题，在MonitorWindow的XAML代码中删除了属性WindowState =“Maximized”，并按如下方式更改了程序：

        Queue<string> itemQueue = new Queue<string>();

        MonitorWindow monitor = new MonitorWindow(itemQueue);

        var secondaryScreen = System.Windows.Forms.Screen.AllScreens.Where(s => !s.Primary).FirstOrDefault();

        if (secondaryScreen != null)
        {
            if (!monitor.IsLoaded)
                monitor.WindowStartupLocation = WindowStartupLocation.Manual;
            var workingArea = secondaryScreen.WorkingArea;
            monitor.Left = workingArea.Left;
            monitor.Top = workingArea.Top;
            monitor.Width = workingArea.Width;
            monitor.Height = workingArea.Height;
            // If window isn't loaded then maxmizing will result in the window displaying on the primary monitor
            monitor.Show();
            if (monitor.IsLoaded)
                monitor.WindowState = WindowState.Maximized;
        }