Question

如果我有这个架构

列表（ lead_id ，list_id，campaign_id，...）
广告系列（campaign_id，...）
custom_list_id（lead_id，...）

对于各种 custom_ ，有许多名称为list_id list_id 的表格，我想：

SELECT * from lists ls inner join campaign c ON c.id=ls.campaign_id
inner join custom_"@LISTID" cll ON ls.lead_id = cll.lead_id

如何撰写此查询？日Thnx

Answer 1

不确定你真正想要的sql，但试试这个：

SET @sql = NULL;
SELECT
  GROUP_CONCAT(DISTINCT
    CONCAT(
      'INNER JOIN custom_',  list_id, 'cll', list_id, ' ON ls.lead_id = cll', list_id '.lead_id')
    )
    SEPARATOR ' '
  ) INTO @sql
FROM lists ;
SET @sql = CONCAT('SELECT * from lists ls inner join campaign c ON c.id=ls.campaign_id ', @sql);
PREPARE stmt FROM @sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;

MYSQL动态表名选择带连接和条件

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