Question

在Play应用程序中收到请求时，我可以像这样打印cookie：

println(request.cookies)

结果是这样的：

Map(PLAY_SESSION -> Cookie(PLAY_SESSION,bd5712f8fb6a7a43935e20f98d6b147181dda9d5-inr=val1&uid=val2,None,/,None,false,true))

我只需要键bd5712f8fb6a7a43935e20f98d6b147181dda9d5，有没有办法在Play中获取它，或者我必须解析字符串？

Answer 1

你可以得到像这样的cookie值：

' Deletes the old table and relinks it
' to the new schema
Sub DeleteRelinkToViewAndRename(loginInfo As AuthInfoz, tblName, tblTarget)

    Dim objAccess As Access.application
    Dim db As DAO.database

    Dim tdf As DAO.TableDef

    ' Open the thing manually first...
    'Shell """C:\Program Files (x86)\Microsoft Office\Office12\MSACCESS.EXE""" & " " & loginInfo.dbs
    Set objAccess = GetObject(loginInfo.dbs).application
    Set db = objAccess.CurrentDb

    ' Delete the Linked Table...THIS WORKS UNCOMMENT LATER...
    objAccess.DoCmd.DeleteObject acTable, tblName

    ' Relink the old table to the new schema
    Set tdf = db.CreateTableDef(tblName, 0, tblTarget, "ODBC;DSN=MEDSN;Database=MEDATABASE;Trusted_Connection=Yes")

    ' Add the new table def
    db.TableDefs.Append tdf

End Sub

如果你只想获得钥匙

val cookieValue = request.cookies.get(KEY) match {
        case Some(cookie) => cookie.value
        case None => ""
}

获取Play for Scala中的cookie字符串键

1 个答案: