Question

我已经编写了一个小样本代码来试用pickle模块。在pickle.load（）语句中面对UnicodeDecodeError。编写编码=＆＃39; utf-8＆＃39;也没有效果。这是代码

import pickle

class NewOne:
    def __init__(self):
        self.name = "None"
        self.age = 0

    def entries(self):
        self.name = input("Name: ")
        self.age = input("Age: ")

obj1 = NewOne()
for i in range(3):
    obj1.entries()
    pickle.dump(obj1, open("Details", "ab"))

for j in range(3):
    obj = pickle.load(open("Details",))

    if obj.age == 18:
        print("Name: "+obj.name)

Answer 1

您的代码的主要问题是，每次运行脚本时都要附加到同一文件的末尾，但稍后会加载前三个对象。

实际上，情况比这更糟糕;你应加载前三个对象，但事实上你每次只加载第一个，因为你在pickle.load()的每次迭代中重新打开文件

可能是文件开头有错误，而且您每次只是因为正在加载文件中的第一个对象而触及此错误。您可以尝试删除Details文件，看看是否仍然收到错误。

以下代码每次都会创建一个新的details文件，向其写入三个对象，然后重新加载这三个对象。

import pickle

class NewOne:
    def __init__(self):
        self.name = "None"
        self.age = 0

    def entries(self):
        self.name = raw_input("Name: ")
        self.age = raw_input("Age: ")

obj1 = NewOne()

# Open file for writing. The `with` context manager will automatically close 
# it at the end of the loop
with open("Details", "wb") as myfile:
    for i in range(3):
        obj1.entries()
        pickle.dump(obj1, myfile)

# Re-open the file for reading
with open("Details",) as myfile:
    for j in range(3):
        obj = pickle.load(myfile)

        if obj.age == '18':
            print("Name: "+obj.name)

二进制文件中的UnicodDecodeError

1 个答案: