Question

以下是字符串，我想从字符串中删除前导和尾随'和'字。

String：和121630是ABC 9.0.2.0的一部分，121630包含在DEF和

中

预期产出：121630是ABC 9.0.2.0的一部分，121630包含在DEF中

任何人都可以告诉我该怎么做？

Answer 1

SQL> with tbl(str) as (
      select 'and 121630 is part of ABC 9.0.2.0 and 121630 is included in DEF and' 
      from dual
    )
    select regexp_replace(str, '^and (.*) and$', '\1') fixed_str
    from tbl;

FIXED_STR
-----------------------------------------------------------
121630 is part of ABC 9.0.2.0 and 121630 is included in DEF

SQL>

Answer 2

您可以使用LTRIM和RTRIM功能：

declare 
  lString VARCHAR2(1000);
begin
  lString := 'and 121630 is part of ABC 9.0.2.0 and 121630 is included in DEF and';

  lString := ltrim(lString,'and ');

  lString := rtrim(lString,' and');

  dbms_output.put_line(lString);
end;

Answer 3

我不是regular expression的专家，但这可以工作:)：

SELECT REGEXP_REPLACE (' and 121630 is part of ABC 9.0.2.0 and 121630 is included in DEF and', 
                       '(^\s*and\s*(\s|$))|((^|\s)\s*and\s*$)')  
  FROM DUAL

编辑：对于多个＆＃39;和＆＃39;组成一个小组：

SELECT REGEXP_REPLACE (' and  and   and 121630 is part of ABC 9.0.2.0 and 121630 is included in DEF', 
                       '(^(\s*and\s*)+(\s|$))|((^|\s)(\s*and\s*)+$)')  
  FROM DUAL

从plsql中的字符串中删除前导和尾随单词

3 个答案: