如何在js文件中设置控制器动作的url？

Question

我想从.js文件中调用控制器操作方法。但我得到的URL是一个字符串。它没有将此识别为控制器动作方法？我们如何解决这个问题？

      function updateBlockAsOrphan(invalidHandles) {
    debugger;
    console.log("updateBlockAsOrphan Started..................");
    var url = '@Url.Action("updateBlockAsOrphan", "OpenDrawing", new { area = "Objects" })';        
    var paramswithcomma = invalidHandles.split(rowDelimeter).join(',');
    var params = { BlockRefHandles: paramswithcomma };
    console.log("updateBlockAsOrphan inprogress with data ..................");
    $.ajax({
        type: 'POST',
        url: url,
        data: params,
        success: function (result)
        {
            debugger;
            console.log("Result -" + result.d.length);
            //console.log("REturned Value -" + result.d[0]);
            //console.log("******************************Successhhh******************");

        }
    });



}